Answer:
506
Step-by-step explanation:
:. t6 = 46 ... [ Given ]
tn = a+(n-1) d ... [ Formula ]
:. t6 = a+(6-1) d
:. 46 = a+5d ... [1]
Sn = n/2 [2a+(n-1)d] ... [ Formula ]
:. S11 = 11/2 [2a+(11-1) d]
:. S11 = 11/2 [2a+10d]
:. S11 = 11/2x2 [a+5d]
:. S11 = 11[46] ... [ From (1)]
:. S11 = 506
Answer:
x = s, y = t, z = 8 -s -t
Step-by-step explanation:
It can work reasonably well to let s and t represent any of a pair of the variables. In the answer above, we have used x=s, y=t.
You could get more elaborate if you want:
x = 4-s, y = 4-t, z = s+t
Answer:
False
Step-by-step explanation:
There might be a chance I am wrong though sorr for the inconvinience
Answer:
Step-by-step explanation:
<h3>AP given</h3>
<h3>To find</h3>
<h3>Solution</h3>
Common difference
<u>Difference of first two</u>
- d = (a -b) - (a + b) = -2b
<u>Difference of second two</u>
<u>Difference of last two</u>
<u>Now comparing d:</u>
- -2b = ab - (a - b)
- ab - a = - 3b
- a(1 - b) = 3b
- a = 3b/(1 - b)
and
- a/b - ab = -2b
- a(1/b - b) = -2b
- a = 2b²/(b² - 1)
<u>Eliminating a:</u>
- 2b²/(b² - 1) = 3b/(1 - b)
- 2b/(b+1) = -3
- 2b = -3b - 3
- 5b = - 3
- b = -3/5
<u>Finding a:</u>
- a = 3b/(1 - b) =
- 3*(-3/5) *1/(1 - (-3/5)) =
- -9/5*5/8 =
- -9/8
<u>So the first term is:</u>
- a + b = -3/5 - 9/8 = -24/40 - 45/40 = - 69/40
<u>Common difference:</u>
<u>The 6th term:</u>
- a₆ = a₁ + 5d =
- -69/40 + 5*6/5 =
- -69/40 + 240/40 =
- 171/40 = 4 11/40
<h2>Answer: </h2>
We know that,
Length of arc = 2 × 3.14 × 6 × 45/360
Length of arc = 6.28 × 3/4
= 18.84/4
= 4.71units.
