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Marina CMI [18]
3 years ago
13

suma a trei numere este 3932/Primul numar este cu 1330mai mare decat al doilea si cu 1740mai mare decat al treilea determinati c

ele trei numere vreau rezolvare de clasa a 5 a
Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0
A+b+c= 3932

a=b+1330
a=c+1740 ⇒c=a-1740⇒c=(b+1330)-1740

Obt. 

b+1330 +b+(b+1330)-1740=3932 ⇒3b+2660-1740=3932⇒3b+920=3932⇒3b=3932-920⇒3b=3012⇒b=3012/3⇒\boxed{b=1004}


a=b+1330⇒a=1004+1330⇒\boxed{a=2334}

c=a-1740⇒c=23334-1740⇒\boxed{c=594}
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19

Step-by-step explanation:

Rate 1: 3  

4

1

​  

%=3+1/4=

\,\,3.25\%\rightarrow 0.0325

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\text{Calculate Final Amount for Nevaeh}

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\overline{\phantom{\text{Calculate Final Amount for Nevaeh}}}

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\text{Compounded Continuously:}

Compounded Continuously:

A=Pe^{rt}

A=Pe  

rt

 

P=660\hspace{35px}r=0.0325\hspace{35px}t=14

P=660r=0.0325t=14

Given values

A=660e^{0.0325(14)}

A=660e  

0.0325(14)

 

Plug in

A=660e^{0.455}

A=660e  

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Multiply

A=1040.2744

A=1040.2744

Use calculator (with e button)

\text{Calculate Final Amount for Jonathan}

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\text{Compounded Monthly:}

Compounded Monthly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

​  

)  

nt

 

Compound interest formula

P=660\hspace{35px}r=0.03125\hspace{35px}t=14\hspace{35px}n=12

P=660r=0.03125t=14n=12

Given values

A=660\left(1+\frac{0.03125}{12}\right)^{12(14)}

A=660(1+  

12

0.03125

​  

)  

12(14)

 

Plug in values

A=660(1.0026042)^{168}

A=660(1.0026042)  

168

 

Simplify

A=1021.6468

A=1021.6468

Use calculator

\text{How much more money Nevaeh has:}

How much more money Nevaeh has:

1040.2744-1021.6468

1040.2744−1021.6468

18.6276

18.6276

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