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WARRIOR [948]
3 years ago
15

What is the common ratio for the sequence 20,10,5,2.5,...?

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0
12 always constant for
sveticcg [70]3 years ago
3 0

Answer:

Geometric Sequence 20, 10, 5, 2.5, ...

First term, a 20

Common ratio, r

10 ÷ 20  = 0.5 5 ÷ 10 = 0.5 etc.

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3 years ago
1. In ABC, A=45 degrees, B=75 degrees, and BC=12. What is the length of AB?
Aleksandr-060686 [28]

We know that sum of the interior angles of any triangle equal 180° :

So :

A + B + C = 180°

45° + 75° + C = 180°

120° + C = 180°

Both sides minus ( 120°) :

C = 180° - 120°

C = 60°

_________________________________

According to the theorem of sinuses :

\frac{AB}{ \sin(C) } =  \frac{BC}{ \sin(A) } \\

\frac{AB}{ \sin(60) } =  \frac{12}{ \sin(45) } \\

\frac{AB}{ \frac{ \sqrt{3} }{2} } =  \frac{12}{ \frac{ \sqrt{2} }{2} } \\

Multiply \:  both \:  sides \:  by \:   \frac{ \sqrt{3} }{2}

AB =  \frac{24}{ \sqrt{2} } \times  \frac{ \sqrt{3} }{2} \\

AB =  \frac{12 \sqrt{3} }{ \sqrt{2} } \\

AB =  \frac{2 \times 6 \sqrt{3} }{ \sqrt{2} } \\

AB =  \frac{ ({ \sqrt{2} })^{2} \times 6 \sqrt{3}  }{ \sqrt{2} }  \\

AB =  \frac{ \sqrt{2} \times  \sqrt{2} \times 6 \sqrt{3}   }{ \sqrt{2} } \\

AB =  \frac{ \sqrt{2} \times  6 \sqrt{3}   }{1} \\

AB =  \sqrt{2} \times 6 \sqrt{3}

AB = 6 \sqrt{2 \times 3}

AB = 6 \sqrt{6}

_________________________________

I think this is the correct answer.

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0
4 years ago
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