6, 9, 9, 12, 18, 24, 24, 24, 37
37-6= 31
Answer:
(-1, 7) and (-6, -14) are solutions
If m ACD = 30 => m DCB = 60.
In triangle ACD:



AC^{2}+CB^{2}=AB^{2} => AB=

=32.
=> P=16+32+

=48 +

.
2 x 5/ 50 x 18
10 / 900
Divide both by 10
1/90
1. The withdrawals adds up to 291+99+150+12= 552
500-552= -52
2. The bus pass which cost $150.
3.1000-552= $448 left
4.1000-552-300-150=$-2 left. Withdrawal had happened.