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Sonbull [250]
3 years ago
11

F(x) = -3x – 1 g(x) = 3x2 – 5x + 14 Find: f(g(x))

Mathematics
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

Step-by-step explanation:

f(x)=-3x-1

g(x)=3x²-5x+14

f(g(x))

f(3x²-5x+14)

3(-3x-1)²-5(-3x-1)+14

3(9x²+6x+1)+15x+5+14

27x²+18x+3+15x+19

f(g(x))=27x²+33x+22

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Hi what is the answer please to this question
Natali5045456 [20]

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B

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3 0
3 years ago
17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II
maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

9.5x + 6.5(x+c) < 8   when c>0

Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

4 0
3 years ago
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What is "The relationship between time and the distance Remaining on a 3 mile walk for someone walking at a steady rate of 2 mph
FromTheMoon [43]

Answer:

Let d be the remaining distance.

Let t be the remaining time.

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d = rt

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d = 2t

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The remaining time is 1.5 hours.

At the end of the walk, the remaining distance is 0 miles.

The remaining time is 0 hours.

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The graph of this would be a solid line

5 0
3 years ago
Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb
jonny [76]

Answer:  The answer is 400  blue marbles.


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n_b=560-364=196.

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

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Thus, 400 blue marbles need to be added to the bag.


5 0
4 years ago
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