The set of side lengths that form a right triangle is 7, 24, 25
Explanation:
We can solve this using the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, a^2 + b^2 = c^2. We can plug each set of numbers into the equation, one by one, to see if the set of numbers is true in the equation. One thing to note is that the largest number out of the set is always the hypotenuse, or c. The other numbers are the legs (a and b.)
5, 11, 13
a^2 + b^2 = c^2
(5)^2 + (11)^2 = (13)^2
25 + 121 = 169
146 ≠ 169
Since 146 doesn't equal 169, this is NOT a right triangle
9, 24, 25
a^2 + b^2 = c^2
(9)^2 + (24)^2 = (25)^2
81 + 576 = 625
657 ≠ 625
Since 657 doesn't equal 625, this is NOT a right triangle
7, 24, 25
a^2 + b^2 = c^2
(7)^2 + (24)^2 = (25)^2
49 + 576 = 625
625 = 625
This equation is true, because 625 = 625. Therefore this IS a right triangle.
The triangle is isosceles so m∠A and m∠C are the same.
So to find ∠B, we do 74 + 74 + b = 180
148 + b = 180
b = 180 - 148
b = 32
Answer B is the right choice.
Answer:
The length of side BC is 2.8 units
Step-by-step explanation:
* Lets revise how to find the distance between two points
- If there are two points their coordinates are (x1 , y1) and (x2 , y2),
then we can find the distance between them by this rule:
d = √[(x2 - x1)² + (y2 - y1)²]
- Now lets solve the problem
∵ B = (3 , 3)
∵ C = (5 , 1)
- To find the length of BC use the rule of the distance above
- Let point B is (x1 , y1) and point C is (x2 , y2)
∵ x1 = 3 and x2 = 5
∵ y1 = 3 and y2 = 1
∴ BC = √[(5 - 3)² + (1 - 3)²]
∴ BC = √[(2)² + (-2)²]
∴ BC = √[4 + 4] = √8 = 2.8 units
* The length of side BC is 2.8 units
Answer:
71.4 in ^2
Step-by-step explanation:
area of the circles = πr^2
3.14(4x4) = 50.24 but you only have half so divide by 2
= 25.12
second circle
3.14(2x2)= 13.56 again you only have half so divide by 2
= 6.28
square
5x8 = 40
add them all up
25.12+6.28+40 = 71.4
