Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.
So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!
Answer: x=1, y=1
Factor the Polynomial by solving x^2 + bx + c = 0.
m^2 - mv - 56v^2
Factor by grouping.
(m−8v)(m+7v).
x^2 + bx + c = 0
Answer:
-4, 2, -1
Step-by-step explanation:
everything is being multiplied by -1/2
32 × -1/2 = -16
-16 × -1/2 = 8
So 8 × -1/2 = -4
I am not 100% positive but from what I remember learning I think the answer you are looking for on the first question is C.
