Answer:
12 year old is the youngest sibling
Step-by-step explanation:
Given: The ages of three siblings are all consecutive integers.
The sum of sibling´s age is 39.
Now, finding the age of youngest sibling.
Lets assume the age of youngest sibling be "x"
As given, The ages of three siblings are all consecutive integers.
∴ Age of 2nd sibling will be 
Age of 3rd sibling will be 
next, forming an equation for the sum of sibling´s age.
⇒
Opening the parenthesis
⇒ 
⇒
Subtracting both side by 3
⇒
⇒
Dividing both side by 3
⇒
∴ x= 12
Subtituting the value of x to find the age of other sibling
∴Youngest sibling age= 12 years
2nd sibling age= 13 years
3rd sibling age= 14 years
Hence, The youngest sibling is 12 years old.
Here's link to the answer:
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The answer is c 6+15x+15x
Answer:
Step-by-step explanation:
Pythagorean theorem: base ² +altitude² = hypotenuse²
1) hypotenuse² = base² + altitude²
x² = 6² + 3²
= 36 + 9
= 45
x = √45
x = 6.7 cm
4) base ² +altitude² = hypotenuse²
x ² + 3.7 ² = 4.2 ²
x ² + 13.69 = 17.64
x ² = 17.64 - 13.69 = 3.95
x = √3.95
x = 1.99 cm
10)c ² = a ² + b ²
= 3 ² +4 ²
= 9 + 16
c ² = 25
c = √25 = 5
11) a ² + b ² = c ²
9 ² +b² = 13 ²
81 + b² = 169
b² = 169 - 81 = 88
b = 9.38
12) a² + b² = c²
12² + b² = 22²
144 + b² = 484
b² = 484 - 144 = 340
b =√340 = 18.44
Solve for x by simplifying both sides of the equation, then isolating the variable
a. -94