Question

Dy If y - 2x+3 then 3x+29 dx

Answer 1

Answer:

$y'=\frac{-5}{(3x+2)^2}$

Step-by-step explanation:

Step 1: Write equation

$y=\frac{2x+3}{3x+2}$

Step 2: Find derivative

1. Quotient Rule: $y'=\frac{(3x+2)(2)-(3)(2x+3)}{(3x+2)^2}$
2. Simplify: $y'=\frac{(6x+4)-(6x+9)}{(3x+2)^2}$
3. Simplify: $y'=\frac{-5}{(3x+2)^2}$