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Andrew [12]
4 years ago
11

When Sam’s assistant was collecting the data she mistakenly noted that the oldest person was 48. The oldest person was actually

50. How will this affect the box plot? Bonus: Sam wants to know if there are any outliers in the data. What would the upper and lower fences be for this set of data?
Mathematics
1 answer:
Luden [163]4 years ago
7 0
I think that the answer is 2400. hope it help???
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Miya is selling grapefruit and nuts for a fundraiser. The grapefruits cost 5 dollars each and a bag of nuts cost 15 dollars each
anyanavicka [17]

Answer:

A) 5G + 15N = 250

B) G + N = 30   We'll multiply B) by -5

B) -5G -5N = -150  then we add A)

A) 5G + 15N = 250

10N = 100

N = 10 bags of nuts ($150.00)

We put N=10 into A)

A) 5G + 150 = 250

A) 5G = 100

G = 20 Grapefruits ($100.00)

Step-by-step explanation:

6 0
3 years ago
Change the following decimal to a fraction. Express your answer like the following example (ex: 9.5 = 9 1/2) 4.125 = ?
user100 [1]

Step-by-step explanation:

4  +  \frac{125}{1000}  = 4 +  \frac{1}{8}  \\ thank \: you

7 0
3 years ago
Read 2 more answers
Kaitlin will donate up to $460 to charity. The money will be divided between two charities: the City Youth Fund and the Educatio
Ganezh [65]

Answer:

The question states "up to $460" in charity, which means it can be less than or equal to 460, but not any higher. Then,

$460 to charity (max)

$160+ to Educational (160 being the minimum)

Education is 3x (or higher) than City.

If we denote x to City, and y to Educational, then,

x + y = 460 . And we know that y >= 3x

x + 3x = 4x = 460

x = 115. This means when she donates $115 to City, she will donate 3x (or $345) to Educational. These are the max values; she will not donate higher than $460.

A minimum requirement was placed on Educational earlier. When y = 160, x will be y/3, or $53.34. (This isn't very meaningful, but: This means she donated 213.34, which is still less than $460)

Therefore, x (which is City) can be the range of $53-ish dollars (depending on your region/graph) but no higher than $115.

y (which is Educational) will be as low as $160, but no higher than $345.

Hope this helps

5 0
3 years ago
Iodine-125 has a half-life of about 60 days. How many milligrams of a 500 mg sample will remain after 300 days?
just olya [345]

60 x 5 = 300 days

So five half-lifes = 300 days

Starting amount = 500mg

<span>Amount after 1st half-life = 250 mg</span>

<span>Amount after 2nd half-life = 125 mg</span>

<span>Amount after 3rd half-life = 62.5 mg</span>

<span>Amount after 4th half-life = 31.25 mg</span>

<span>Amount after 5th half-life = 15.625 mg</span>

<span>Hence after 300 days, the amount of iodine-125 will be 15.625 mg out of 500 mg.</span>

4 0
3 years ago
Read 2 more answers
How to do this i need help
astraxan [27]

Step-by-step explanation:

<h2 /><h2>AREA OF TRIANGLE </h2>

= 1/2× BASE× HEIGHT

= 1/2×25×50 yd²

= 625 yd²

6 0
3 years ago
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