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Nina [5.8K]
3 years ago
12

X^2-14x+49 as a graph

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0
<span> -x^2 + -14x = 49
-(x^2 +14) = 49
-[(x+7)^2 -49] = 49
</span>
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The cost of controlling emissions at a firm is given by:
shepuryov [24]

Answer:

The correct answer is 0.5 pounds of pollutant.

Step-by-step explanation:

According to the problem the cost of controlling emissions at a firm is given by:

C(q) = 1,260 + 100 × q^{2} , where q is the reduction in emissions (in pounds of pollution per day) and C is the daily cost to the firm (in dollars) of this reduction.

Government clean-air subsidies amount to $100 per pound of pollutant removed per day.

Net cost = C(q) - Subsidy

⇒ Net Cost = 1,260 + 100 × q^{2} - 100 × q.

In order to minimize net cost we calculate,  \frac{d}{dq}(Net cost) = 0.

⇒ 200 × q - 100 = 0

⇒ q = 0.5

We can see that the second order derivative is positive and thus the net cost minimizes.

Thus the firm should remove 0.5 pounds of pollutant each day in order to minimize net cost.

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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dedylja [7]

Answers:

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6 0
3 years ago
List 3 value that would make this inequality true 8n+4 greater than or equal to 28
tiny-mole [99]
8n + 4 >= 28

8n >= 24

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Values of n which makes this inequality true could be 3,4 and 5.
3 0
3 years ago
Read 2 more answers
The length of a picture frame is 6 inches more than the width. For what values of x is the perimeter of the picture frame greate
aniked [119]

Answer:

x > 36 in

Step-by-step explanation:

         Let x = the width of the picture frame.

Then x + 6 = the length of the frame.

The formula for the perimeter P of a rectangle is'

P = 2l + 2w.

So, the condition is

    2l     + 2w > 156

2(x + 6) + 2x  > 156     Distribute the 2

2x + 12 + 2x  > 156     Combine like terms

       4x + 12  > 156     Subtract 12 from each side

               4x > 144     Divide each side by 4

                x >  36

The perimeter of the picture frame will be greater than 156 in if x > 36 in.

5 0
4 years ago
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