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VMariaS [17]
3 years ago
11

Find the sum of vectors u = <-2, 6> and v = <4, -9>, and then find the magnitude of u + v.

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

u + v = <2, -3>

Magnitude: |u+v| = \sqrt{13}

Step-by-step explanation:

If there are 2 vector:

a = <b,c>

and

z = <x,y>

Then a + z is  <b+x,c+y>

Also, the magnitude would be

|a+z| = \sqrt{(b+x)^2 + (c+y)^2}

Now, let find the sum for the problem shown:

u + v = <-2+4, 6 -9>

u + v = <2, -3>

And the magnitude is:

|u+v| = \sqrt{(2)^2 + (-3)^2}=\sqrt{13}

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Divide x^3 -3x^2 by x-2<br> . Step 1 - Fill in the missing number:
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Answer:


Step-by-step explanation:

First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items

F(x) = x^3-3x^2+0x+0

We have to divide this by x-2

Leading terms in the dividend and divisor are

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                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

                                                         ---------------

-x^2+0x

Again take the leading terms and find quotient is –x

                                                x-2) x^3-3x^2+0x+0(x^2-x

x^3-2x^2

                                                         ---------------

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                                                                  -x^2-2x

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