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VMariaS [17]
3 years ago
11

Find the sum of vectors u = <-2, 6> and v = <4, -9>, and then find the magnitude of u + v.

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

u + v = <2, -3>

Magnitude: |u+v| = \sqrt{13}

Step-by-step explanation:

If there are 2 vector:

a = <b,c>

and

z = <x,y>

Then a + z is  <b+x,c+y>

Also, the magnitude would be

|a+z| = \sqrt{(b+x)^2 + (c+y)^2}

Now, let find the sum for the problem shown:

u + v = <-2+4, 6 -9>

u + v = <2, -3>

And the magnitude is:

|u+v| = \sqrt{(2)^2 + (-3)^2}=\sqrt{13}

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X = 22 + 10x<br> How to find x?
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Answer:

x = -2.44

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract 10x from both sides:

x (-10x) = 22 + 10x (-10x)

x - 10x = 22

-9x = 22

Isolate the variable, x. Divide -9 from both sides:

(-9x)/-9 = (22)/-9

x = 22/-9

x = -(22/9)

x = -2.44 (repeating).

x = -2.44 (rounded) is your answer.

~

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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The constant of proportionality is the ratio between two directly proportional quantities

  • If x and y are in directly proportion, then \frac{y}{x}=k , where k is the constant of proportionality.
  • The direct proportion can be represented by a line whose equation is y = kx, where k is the slope of the line.

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∴ \frac{18}{4}=k

→ Simplify the fraction by dividing up and down by 2

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