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VMariaS [17]
3 years ago
11

Find the sum of vectors u = <-2, 6> and v = <4, -9>, and then find the magnitude of u + v.

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

u + v = <2, -3>

Magnitude: |u+v| = \sqrt{13}

Step-by-step explanation:

If there are 2 vector:

a = <b,c>

and

z = <x,y>

Then a + z is  <b+x,c+y>

Also, the magnitude would be

|a+z| = \sqrt{(b+x)^2 + (c+y)^2}

Now, let find the sum for the problem shown:

u + v = <-2+4, 6 -9>

u + v = <2, -3>

And the magnitude is:

|u+v| = \sqrt{(2)^2 + (-3)^2}=\sqrt{13}

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The number of lattes sold daily by two coffee shops is shown in the table.
Gre4nikov [31]

Answer:

The correct option is B.

Step-by-step explanation:

The number of lattes sold daily by two coffee shops is shown in the table.

The data set for shop A is

55, 52, 56, 48, 57, 30, 45, 41

Arrange the data in ascending order.

30, 41, 45, 48, 52, 55, 56, 57

Mean of shop A is

Mean=\frac{\sum x}{n}=\frac{30+41+45+48+52+55+56+57}{8}=48

Median=\frac{(\frac{n}{2})th+(\frac{n}{2}+1)th}{2}=\frac{48+52}{2}=50

The data set for shop B is

45, 42, 57, 48, 11, 10, 46, 43

Arrange the data in ascending order.

10, 11, 42, 43, 45, 46, 48, 57

Mean of shop A is

Mean=\frac{\sum x}{n}=\frac{10+11+42+43+45+46+48+57}{8}=37.75

Median=\frac{(\frac{n}{2})th+(\frac{n}{2}+1)th}{2}=\frac{43+45}{2}=44

Both data distribution are not symmetric, so it is better to describe the centers of distribution in terms of median for both coffee shops. Therefore the correct option is B.

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shepuryov [24]

Answer: I think Figure 4 is the correct one

Step-by-step explanation:

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Answer:

14

Step-by-step explanation:

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