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Salsk061 [2.6K]
3 years ago
14

What is the distance d across the lake?

Mathematics
1 answer:
Ber [7]3 years ago
4 0

<u>Answer-</u>

<em>The distance d across the lake is </em><em>90ft.</em>

<u>Solution-</u>

In the picture,

ΔABC ≈ ΔCDE

Because,

  1. ∠ACB = ∠DCE (∵ vertical opposite angles)
  2. ∠B = ∠D = 90°
  3. ∠ACB = ∠CED (∵ as other two angles are same and sum of those two angles when subtracted from 180° will result the same)

So, from similarity properties

\Rightarrow \dfrac{AB}{DE}=\dfrac{BC}{DC}

\Rightarrow \dfrac{120}{20}=\dfrac{d}{15}

\Rightarrow d=\dfrac{120\times 15}{20}=90

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