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Harlamova29_29 [7]
3 years ago
12

Arlene writes this problem:

Mathematics
1 answer:
fredd [130]3 years ago
5 0

it looks like its answers two, four, and five.

tell me how you did !

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Numbers 6,7,8 I can't figure out
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6. Take your compass and place the pointed edge on point B. Place one point on each side of B, each the same distance away from B. Next, place your compass on one of the two new points and extend your compass to draw a circle. Repeat with the SAME radian from the other point. Find where the two circles intersect with each other and draw a line from the points of intersection to point B. Place point A anywhere on that line that you just created and then you're done!

7. Select any place along either line and place point S on it. Next, using the same method as above, draw two circles with the same radius around both points S and R. Draw a line through the intersection points. Locate the intersection where your new line connects with the line across from the shared line of RS. Place a point at the intersection, for your reference, then connect that point to point S. Now you have completed this problem as well.

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1 year ago
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3 years ago
What is the other square root of 119 + 120i?
MakcuM [25]

Answer:

\sqrt{119+120 i}=\pm (12.24+i 4.90)

Step-by-step explanation:

Given

z = 119 + 120 i

Let \sqrt{119+120 i}=p+iq

Squaring both sides

119+120 i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

119=p^2-q^2...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

q=\frac{60}{p}

Substitute q in 1

119=p^2-(\frac{60}{p})^2

p^4-119p^2-(68)^2=0

Let x=p^2

x^2-119x-4624=0

x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}

x=\frac{119\pm 180.71}{2}

we take only Positive value because p^2=x

x=149.85  

p^2=149.85

thus p=\pm 12.24

q=\pm 4.90

thus,

\sqrt{119+120 i}=\pm (12.24+i 4.90)

8 0
3 years ago
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