One day , the tempeture ranged from a high of 20 degrease to a low of -25F. By how many degrees did the tempeture change?
1 answer:
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Answer:
The percentage increase in Area of rectangle is 200%
Step-by-step explanation:
Given as :
The ratio of the width to the length of a rectangle is 2:3
Let The length of rectangle = 2 x
Let The width of rectangle = 3 x
∵ Area of rectangle = length × width
So, = 2 x × 3 x
Or, = 6 x²
<u>Again</u>
The increased length of rectangle = 2 x + 2 x = 4 x
The increase width of rectangle = 3 x + 50% of 3 x
I.e The increase width of rectangle = 3 x + 1.5 x = 4.5 x
∵ Increased Area of rectangle = increased length × increased width
Or, = 4 x × 4.5 x = 18 x²
So, The percentage increase in area = × 100
Or, The percentage increase in area = × 100
Or , The percentage increase in area = × 100
∴ The percentage increase in area = 200
Hence, The percentage increase in Area of rectangle is 200% Answer
Here's our equation.
We want to find out when it returns to ground level (h = 0)
To find this out, we can plug in 0 and solve for t.
So the ball will return to the ground at the positive value of
seconds.
What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!
We want to find out when it returns to ground level (h = 0)
To find this out, we can plug in 0 and solve for t.
So the ball will return to the ground at the positive value of
What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!