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bonufazy [111]
3 years ago
8

One day , the tempeture ranged from a high of 20 degrease to a low of -25F. By how many degrees did the tempeture change?

Mathematics
1 answer:
Llana [10]3 years ago
7 0
The temperature changed 45 degrees
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What is the slope of the line (9,-6) and (-6- -9)?
Vlada [557]

Answer:

1/5

Step-by-step explanation:

Slope formula = (y2-y1)/(x2-x1)

((-6)- (-9))/ ((9)-(-6)

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3/15

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Here is the right photo please help i need this before july 1st thank you
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i hope this helps

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4 0
4 years ago
Help me solve this please
shutvik [7]

Answer:

D'G' = 52.5 units

Step-by-step explanation:

Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5

D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )

G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )

Calculate D'G' using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)

D'G' = \sqrt{(-28-3.5)^2+(-17.5-24.5)^2}

       = \sqrt{(-31.5)^2+42^2}

       = \sqrt{992.25+1764}

        = \sqrt{2756.25}

         = 52.5 units

7 0
3 years ago
Please show your work please
Nadusha1986 [10]
The correct answer is 4. 
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3 years ago
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