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castortr0y [4]
3 years ago
13

How do you solve question 26?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

Insert the point (-2, 3)

2·a·(-2) - b·3 - 5 = 0 --> - 4·a - 3·b - 5 = 0 --> 8·a + 6·b + 10 = 0

b·(-2) + 3·a·3 - 15 = 0 --> 9·a - 2·b - 15 = 0 --> 27·a - 6·b - 45 = 0

I + II

35·a - 35 = 0 --> a = 1

8·1 + 6·b + 10 = 0 --> b = -3


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write an equation for the line that passes through the given point and has the given slope m (4,-5);m= -1/4
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-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{y = -1/4x - 4}

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Given: \textsf{Slope = -1/4, Point through = (4, -5)}

Find:  \textsf{Equation for the line that passes through the given point}

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

<u>Plug in the values</u>

  • \textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}
  • \textsf{y - (-5) = -1/4(x - 4)}

<u>Simplify and solve for y</u>

  • \textsf{y + 5 = -1/4(x - 4)}
  • \textsf{y + 5 = -1/4x + 1}
  • \textsf{y + 5 - 5 = -1/4x + 1 - 5}
  • \textsf{y = -1/4x - 4}

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

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