All categories

3 years ago

How do you solve question 26?

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

5 0

Answer:

Insert the point (-2, 3)

2·a·(-2) - b·3 - 5 = 0 --> - 4·a - 3·b - 5 = 0 --> 8·a + 6·b + 10 = 0

b·(-2) + 3·a·3 - 15 = 0 --> 9·a - 2·b - 15 = 0 --> 27·a - 6·b - 45 = 0

I + II

35·a - 35 = 0 --> a = 1

8·1 + 6·b + 10 = 0 --> b = -3

You might be interested in

What is the slope of a vertical line

BlackZzzverrR [31]

JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+ JUMPOUTDAHOUSE*^+

4 0

3 years ago

Read 2 more answers

Factorise the following.

spin [16.1K]

Answer:

x²(9x– 11)(9x + 11)

Step-by-step explanation:

81x⁴ – 121x²

The expression can be factorised as follow:

81x⁴ – 121x²

x² is common to both term. Thus:

81x⁴ – 121x² = x²(81x² – 121)

Recall:

81 = 9²

121 = 11²

Therefore,

x²(81x² – 121) = x²(9²x² – 11²)

= x²[(9x)² – 11²]

Difference of two squares

x²(9x– 11)(9x + 11)

Therefore,

81x⁴ – 121x² = x²(9x– 11)(9x + 11)

3 0

3 years ago

000

grigory [225]

Answer:

Step-by-step explanation:

4 0

3 years ago

If the area of a square with side x is equal to the area of a triangle with base x, then find the altitude of the triangle.

zhannawk [14.2K]

Answer:

$h= 2x$

Step-by-step explanation:

Given

Square

$Side = x$

Triangle

$Base = x$

$Altitude = h$

Required

Find h, if both shapes have the same area

The area of the square is:

$Area = x * x$

$Area = x^2$

The area of the triangle is:

$Area = \frac{1}{2} * Base*Height$

$Area = \frac{1}{2} * x*h$

Equate both areas

$x^2 = \frac{1}{2} * x*h$

Divide both sides by x

$x = \frac{1}{2} *h$

Multiply both sides by 2

$2*x = \frac{1}{2} *h*2$

$2x = h$

$h= 2x$

3 0

2 years ago

Enter the explicit rule for the sequence

Softa [21]

Let's take a look at the first few numbers in the sequence based on the given rule:

$a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)$

Inspecting this pattern it seems like the power $\frac{1}{4}$ is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be $\big(\frac{1}{4} \big)^{n-1}$ . We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

$a_n=6\big( \frac{1}{4} \big)^{n-1}$

Where $a_n$ is the nth number in our sequence.

8 0

3 years ago