3 years ago

How do you solve question 26?

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

5 0

Answer:

Insert the point (-2, 3)

2·a·(-2) - b·3 - 5 = 0 --> - 4·a - 3·b - 5 = 0 --> 8·a + 6·b + 10 = 0

b·(-2) + 3·a·3 - 15 = 0 --> 9·a - 2·b - 15 = 0 --> 27·a - 6·b - 45 = 0

I + II

35·a - 35 = 0 --> a = 1

8·1 + 6·b + 10 = 0 --> b = -3

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