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castortr0y [4]
3 years ago
13

How do you solve question 26?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

Insert the point (-2, 3)

2·a·(-2) - b·3 - 5 = 0 --> - 4·a - 3·b - 5 = 0 --> 8·a + 6·b + 10 = 0

b·(-2) + 3·a·3 - 15 = 0 --> 9·a - 2·b - 15 = 0 --> 27·a - 6·b - 45 = 0

I + II

35·a - 35 = 0 --> a = 1

8·1 + 6·b + 10 = 0 --> b = -3


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jeka94

Assignment: \bold{Solve \ \left(-2x^2\right)^3\cdot \:3x}

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Answer: \boxed{\bold{-24x^7}}

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Explanation: \downarrow\downarrow\downarrow

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[ Step One ] Rewrite \bold{\left(-2x^2\right)^3}

\bold{-2^3\left(x^2\right)^3}

[ Step Two ] Rewrite Equation

\bold{-2^3\cdot \:3x^6x}

[ Step Three ] Apply Exponent Rule

Note: \bold{Exponent \ Rule \ \:a^b\cdot \:a^c=a^{b+c}: \ x^6x=\:x^{6+1}=\:x^7}

\bold{-2^3\cdot \:3x^7}

[ Step Four ] Refine

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4 0
3 years ago
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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3 years ago
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