$\frac{1}{6}x+\frac{1}{3}x+\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=x\\\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=27\\\frac{3}{7}(x-(\frac{1}{2}x))=27\\\frac{3}{7}(\frac{1}{2}x)=27\\x=126$

126 caps

5 0

3 years ago

The Martinez family went to play and paid $13 for 1 adult and 4 children. The Hernandez family went to the same place and paid $

andrey2020 [161]

Answer: the price for an adult ticket is $3

Step-by-step explanation:

Let x represent the price of one adult ticket.

Let y represent the price of one child ticket.

The Martinez family went to play and paid $13 for 1 adult and 4 children. This means that

x + 4y = 13 - - - - - - - - - - -1

The Hernandez family went to the same place and paid $14 for 3 adults and 2 children. This means that

3x + 2y = 14 - - - -- - - - - - - -2

Multiplying equation 1 by 3 and equation 3 by 1, it becomes

3x + 12y = 39

3x + 2y = 14

Subtracting, it becomes

10y = 25

y = 25/10 = 2.5

Substituting y = 2.5 into equation 1, it becomes

x + 4 × 2.5 = 13

x + 10 = 13

x = 13 - 10

x = 3

6 0

3 years ago