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2 years ago

Is 17 1/2 to the right or left of 17 2/3 on the number line? Explain your answer.

Mathematics

2 answers:

liberstina [14]2 years ago

8 0

7 1/2 is to the left of 17 2/3 on a number line because 7 1/2 is less then 17 2/3

bearhunter [10]2 years ago

6 0

17 2/3 is greater than 17 1/2
so
<span> 17 1/2 is to the left of 17 2/3 on the number line</span>

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Can someone actually help with this not traditional reference angle question please I will give lots of points and will make you

melomori [17]

Answer:

Step-by-step explanation:

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2 years ago

9. If f(x) = 5x-4 and f(2a) =156 , then what is the value of a?

solmaris [256]

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$f(x) = 5x - 4$

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$f(2a) = 5(2a) - 4$

$f(2a) = 10a - 4$

$156 = 10a - 4$

$10a - 4 = 156$

Add sides 4

$10a - 4 + 4 = 156 + 4$

$10a = 160$

Divide sides by 10

$\frac{10a}{10} = \frac{160}{10} \\$

$a = 16$

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2 years ago

joe and marty are in the park playing catch. tony joins them, and the boys want to stand so that the distance between any two of

Snezhnost [94]

Answer:

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2 years ago

Which two functions are inverses of each other?

liraira [26]

Answer:

Option 3 - f(x)= 4x, $g(x) = \frac{1}{4}x$

Step-by-step explanation:

To find : Which two functions are inverses of each other?

Solution :

Two functions are inverse if $f(g(x))=x=g(f(x))$

Now, we find one by one

1) f(x)= x, g(x) = -x

$f(g(x))=f(-x)=-x\neq x$

Not true.

2) f(x)= 2x, $g(x) = -\frac{1}{2}x$

$f(g(x))=f(-\frac{1}{2}x)=2\times(-\frac{1}{2}x)=-x\neq x$

Not true.

3) f(x)= 4x, $g(x) = \frac{1}{4}x$

$f(g(x))=f(\frac{1}{4}x)=4\times(\frac{1}{4}x)=x$

$g(f(x))=f(4x)=\frac{1}{4}\times 4x=x$

i.e. $f(g(x))=x=g(f(x))$ is true.

So, These two functions are inverse of each other.

4) f(x)= -8x, $g(x) =8x$

$f(g(x))=f(8x)=8\times(-8x)=-64x\neq x$

Not true.

Therefore, Option 3 is correct.

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2 years ago

Order the numbers 21 , 40, and 42 from least to greatest based on how many numbers are in their prime factorization.

lora16 [44]

Answer:

21,40,42

Step-by-step explanation:

That's it.Wish it's correct.:D

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2 years ago