2 years ago

Which is the net force acting on a 1.7-kg object that is accelerating at 5.0 m/s??

1 answer:

4 0

Answer:

A. 8.5 N

Step-by-step explanation: F = 8.5 N

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olganol [36]

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (-1, 8) and (5, -2). Substitute:

$d=\sqrt{(5-(-1))^2+(-2-8)^2}=\sqrt{6^2+(-10)^2}=\sqrt{36+100}=\sqrt{136}\\\\=\sqrt{4\cdot34}=\sqrt4\cdot\sqrt{34}=\boxed{2\sqrt{34}}$

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3 years ago

max2010maxim [7]

You have to use subtraction because it says how many

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3 years ago

Irina-Kira [14]

Slopt in form ax+by=c is -a/b
-3/3=-1
slope is -1
intercept in form ax+by=c is c/b
63/3=9

slope is -1
intercept is at y=9

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3 years ago

Veronika [31]

The answer will be c

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3 years ago

Arturiano [62]

Correct me if I’m wrong but I’d go with
B). 34, 55

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3 years ago