Dennis has a 12-foot board. He cuts it down into pieces that are each 2 feet long.

A scientist from the United States conducts an experiment using miles per hour to measure speed why might this be confusing for

juin [17]

The scientific mathematical language barrier.

4 0

3 years ago

X^3 + 6x + 5 =?? Explain your answer..

vovikov84 [41]

x^3 + 6x + 5 =

is the answer to the question you asked

7 0

3 years ago

The diameter of a sphere is 2,160 mm. The diameter of a second sphere is 7,520 mm. Approximately how many times larger is the vo

fgiga [73]

Answer:

Approximately 42 times larger

Step-by-step explanation:

The diameter of a sphere is 2,160 mm.

The diameter of a second sphere is 7,520 mm.

To see how many times larger is the diameter of second sphere is than the diameter of the second sphere, we divide to get:

$k = \frac{7520}{2160}$

$k = 3.481$

To see how many times larger the volume is, we cube both sides

${k}^{3} = {3.481}^{3}$

This implies that

${k}^{3} = 42.181$

Therefore the volume of the second sphere is approximately 42 times larger

3 0

3 years ago

22. One kilometer is approximately 0.62 mile. What fraction represents this length?

bixtya [17]

Answer:

One kilometer is $\frac{31}{50}$ miles

Explanation:

To convert a decimal to a fraction:

1- Write the decimal as a fraction whose denominator is 1

2- Multiply both numerator and denominator by multiples of 10 to eliminate the decimal point

3- Simplify the fraction you have

Now, for the given problem:

The given decimal is 0.62, following the above steps:

Step 1:

$0.62 = \frac{0.62}{1}$

Step 2:

We have two digits after the decimal point, so to eliminate the decimal point, we will multiply the numerator and the denominator by 100

$0.62 = \frac{0.62}{1} * \frac{100}{100} = \frac{62}{100}$

Step 3:

We can note that, in the fraction obtained from step 2, both the numerator and the denominator are divisible by 2, so we simplify as follows:

$\frac{62}{100} = \frac{62/2}{100/2} =\frac{31}{50}$

Hope this helps :)

6 0

3 years ago

Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)

morpeh [17]

Answer:

$\forall x\in D$ if x is odd then x> 0 is true statement.

$\forall x\in D$ if x is even then x≤0 is false statement.

$\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

$\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) $\forall x\in D$ if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

$\forall x\in D$ if x is odd then x> 0 is true statement.

Part (B) $\forall x\in D$ if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

$\forall x\in D$ if x is odd then x> 0 is true statement.

Part (C) $\forall x\in D$ if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

$\forall x\in D$ if x is even then x≤0 is false statement.

Part (D) $\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

$\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) $\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

$\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0

3 years ago