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ahrayia [7]
3 years ago
15

The mean time it takes for workers at a factory to insert a delicate bolt into an engine is 15 minutes. The standard deviation o

f time to insert the bolt is 4.0 minutes and the distribution of time is approximately Normally distributed. For a randomly selected worker, what is the approximate probability the bolt will be inserted in 19 minutes or less
Mathematics
1 answer:
faust18 [17]3 years ago
6 0

Answer:

required probability is 0.8413

Step-by-step explanation: Given mean \mu =15 minutes, standard deviation \sigma =4 seconds, we need to find P\left ( X\leq 19 \right ). Using z score

z=\frac{X-\mu }{\sigma }\\=\frac{19-15}{4}\\=1

So,

P\left ( X\leq 19 \right )\\=P\left ( Z\leq 1 \right )\\=0.8413

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1 month + 11 months + 3 months + 6 months= 21 months divided by 4 = 5.25
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4 years ago
At a certain non-profit organization, 51% of employees are college graduates and 47% of employees have more than ten years of ex
Lady bird [3.3K]

Answer: 0.21

Step-by-step explanation:

Let A denotes the event that employees are college graduates.

B denotes that the event that employees have more than ten years of experience.

As per given , we have

P(A)=0.51

P(B)=0.47

P(A∪B)=0.77

We know that , P(A\cup B)=P(A)+P(B)-P(A\cap B)

0.77=0.51+0.47-P(A\cap B)

P(A\cap B)=0.51+0.47-0.77=0.21

Hence, the probability that a randomly selected employee will have more than ten years of experience and be a college graduate = 0.21

8 0
3 years ago
What is the answer? Please Answer it?
bezimeni [28]

Answer:

2, 5

Step-by-step explanation:

hope this helps

please mark me brainliest

7 0
3 years ago
What is the following product
Genrish500 [490]

For this case we must find the product of the following expression:

\sqrt [3] {5} * \sqrt {2}

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

We rewrite the expression using the lowest common index of 6, then:

5 ^ {\frac {1} {3}} * 2 ^ {\frac {1} {2}} =

We rewrite the terms in an equivalent way:

5 ^ {\frac {2} {6}} * 2 ^ {\frac {3} {6}} =

We rewrite the expression using the property mentioned:

\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =

We combine using the product rule for radicals:

\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}

So:

\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}

ANswer:

Option b

4 0
3 years ago
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