We evaluate b^2 - 4ac. If the answer is positive, then there are two real solutions. If it is zero, there is one real solution. If it is negative, there are 2 complex solutions. In this equation, a = 1, b = 5, c = 7. Now we plug in the numbers.

Because this answer is positive, there are two real solutions.
2.5418x10^12
you do 9x9x9x9x9x9x9x9x9x9x9x9x9
x=0
4+(x+y)=(4+)+y
4 + x + y = 4 + y
Subtract y from both sides
4 + x + y - y = 4 + y - y
Simplify
4 + x = 4
Subtract 4 from both sides
4 + x - 4 = 4 - 4
Simplify
x = 0
Answer:
828
Step-by-step explanation: