Question

In a 30cm by 25cm rectangle, a quadrant of a circle of radius 7cm has been cut away from each corner. What is the perimeter of the part left? and also what is the area of the part left
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Answer 1

Answer:

Perimeter = 98 cm

Area = 596 $cm^{2}$

Step-by-step explanation:

Please refer to the attached image for the resultant figure when a quadrant of circle with radius 7 cm is cut from a rectangle of sides 30 cm and 25 cm.

Perimeter of a figure = Sum of all its sides + Perimeter of circle

Quadrant of a circle is one fourth of a circle and there are 4 such quadrant of a circle, so eventually there is one complete circle in this figure.

The sides of this resultant figure = 30 - 14 = 16 cm

and 25 - 14 = 11 cm

So perimeter of this figure = 16 + 11 + 16 + 11 + Perimeter of circle

$\Rightarrow 54 + 2 \pi r\\\Rightarrow 54 + 2 \times \dfrac{22}{7} \times 7\\\Rightarrow 54 + 44 = 98 cm$

To find area of this figure = Area of rectangle - Area of circle

Area of rectangle = Length $\times$ Width

$\Rightarrow 30 \times 25 = 750\ cm^{2}$

Area of circle = $\pi r^{2}$

$\Rightarrow \dfrac{22}{7} \times 7^{2} = 154\ cm^{2}$

So, area of figure = 750 - 154 = 596 $cm^{2}$