F(x) = x² - 10x + 24
opens up because coefficient of x² is positive
crosses x-axis at x = 6 and x = 4
crosses y-axis at y = 24
vertex is a minimum at (5, -1)
Solution for the question asked: 3x^2-5x+4=6
it can be simplified by subtracting 6 from both the sides...
3x^2-5x+4-6=6-6
3x^2-5x-2=0 which is the required form where a=3,b=-5 and c=-2.Now putting the values in the formula we will get two values for x which are 6 and (-1).
hope this will help you
Answer:
16
Step-by-step explanation:
6+8+10+20=44+16= 60 divided by 5 is 12
Step-by-step explanation:
The given numbers are : 32 , 48 , 140 , 120
First number is 32
Second number is 48
Third number is 140
Fourth number is 120
First number/second number :
Third number/Fouth number :
From equation (1) and (2) we can see that the ratio is not same. Hence, they are not in proportion.
Answer:
2/7
then 2/14
Step-by-step explanation:
Let P(H)=p be the probability of one head. In many scenarios, this probability is assumed to be p=12 for an unbiased coin. In this instance, P(H)=3P(T) so that p=3(1−p)⟹4p=3 or p=34.
You are interested in the event that out of three coin tosses, at least 2 of them are Heads, or equivalently, at most one of them is tails. So you are interested in finding the likelihood of zero tails, or one tails.
The probability of zero tails would be the case where you only received heads. Since each coin toss is independent, you can multiply these three tosses together: P(H)P(H)P(H)=p3 or in your case, (34)3=2764.
Now we must consider the case where one of your coin flips is a tails. Since you have three flips, you have three independent opportunities for tails. The likelihood of two heads and one tails is 3(p2)(1−p). The reason for the 3 coefficient is the fact that there are three possible events which include two heads and one tails: HHT,HTH,THH. In your case (where the coin is 3 times more likely to have heads): 3(34)2(14)=2764.
Adding those events together you get p3+3(p2)(1−p)=5464. Note that the 3 coefficient
