Answer:
752.95
Step-by-step explanation:
Data provided in the question
The standard deviation of population = 210
The Margin of error = 15
The confidence level is 75%, so the z value is 1.96
Now the required sample size is

= 752.95
Hence, the number of college students spends on the internet each month is 752.95
Simply we considered the above values so that the n could come
Answer:
54
Step-by-step explanation:
BEDMAS
z=10
(10)3-3(2-10)
=(10)3-3(-8)
=30-(-24) *2 negatives = a positive
=30+24
=54
H=3t+10 and h=-16t+15t+6
They will never be at the same height at the same time
45x97=4365 hours, number of hours multiply by n of enmp