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3 years ago

Rewrite the equation for x, and express its value in terms of a. 3/a x - 4 = 20

Mathematics

1 answer:

My name is Ann [436]3 years ago

7 0

For this case, we must clear variable "x" from the given equation, expressed in terms of "a".

We have:

3/a x-4=20

By clearing "x" we have:

Adding 4 to both sides of the equation:

3/a x = 20 + 4

Multiplying by a/3 on both sides of the equation:

x=24a/3

x=8a

So, x=8a

Answer:

x=8a

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7. Ben's earnings for work he did from Monday through Saturday were: $78,

Agata [3.3K]

Answer:Average daily pay =$90

Step-by-step explanation:

Step 1

Formulae

Average daily earnings = Total amount of earning from Monday through Saturday/ number of days

Step 2

Monday $78,

Tuesday $94

Wednesday $115

Thursday $108

Friday $67

Saturday $78

Total earnings for Ben = $540

Average daily pay= $540/6 ==$90

8 0

4 years ago

Find the value of x.<br> (5x + 5)

Ivahew [28]

5( x + 1)

I hope this helps:)

4 0

3 years ago

I need help with this please....Thanks

IrinaK [193]

Answer:

The total cost of redecoration is £66, that is less than £75. Tenant can decorate the room for the budget set.

Step-by-step explanation:

Lets start calculating the areas of shorter and longer walls.

The area of shorter wall is

2.65m*2.98m=7.897m^2.

The area of longer wall is

3.94m*2,65m=10.441m^2.

Together the area of one long and one short wall is

7.897m^2+10.441m^2=18.338m^2.

The area to be painted ( one short and one long wall) is 18.338m^2 that is less than 30m^2, and hence only one tin of paint is needed (costs £16).

If there is assumed that the sheets of wallpaper must be whole from floor to ceiling, the calculations are following.

We get from one roll

10m/2.65m=3.77 sheets; we can use only 3 of them

The width of the walls is 3,94m+2,98m=6,92m,

and division gives 6.92m/0.52m=13,3... .

Hence it requires 14 sheets, that is 5 rolls of wallpaper.

Wallpaper costs 5*£10=£50 and altogether it is needed £50+£16=£66 to redecorate the room.

7 0

3 years ago

A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th

Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

$\tan\theta=\frac{Perpendicular}{base}$

Here, $\theta=11.1^{\circ}$ ,Perpendicular AB = 4000

$\tan\theta=\frac{AB}{BC}$

$\tan 11.1^{\circ} =\frac{4000}{BC}$

Solving for BC, we get,

$BC=\frac{4000}{\tan 11.1^{\circ} }$

$BC=\frac{4000}{0.196}$ (approx)

$BC=20408.16$ (approx)

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0

3 years ago

What is the same as moving the decimal point 3 places to the right in a decimal point.

ladessa [460]

Answer:

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers