The functions would be:
D. y=x³
We can check it out.
(1,1); x=1; y=1 ⇒1=(1)³=1*1*1=1
(2,8); x=2; y=8 ⇒8=(2)³=2*2*2=8
(3,27); x=3; y=27 ⇒27=3³=3*3*3=27
(4,64): x=4; y=64 ⇒64=4³=4*4*4=64
(5,125); x=5; y=125 ⇔ 125=5³=5*5*5=125
Answer:
b. 128°
Step-by-step explanation:
arc LJ = 2 (26) = 52°
arc KL = 180° (half circle)
so
arc JK = 360° - (arc LJ + arc KL)
arc JK = 360° - 232°
arc JK = 128°
Answer
b. 128°
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so .
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when .
So
A task time of 177.125s qualify individuals for such training.
She used two trapezoids.
She put one trapezoid on top and one on the bottom.
The shape she ends up making is a hexagon.