Help me solve it ，thank you.

Ryan purchased a kayak on sale for 130$ before tax. The regular price was 200$ before tax. What percent represents the change is

Norma-Jean [14]

Answer:

70

Step-by-step explanation:

7 0

3 years ago

Help me please thank youu ❤️

Nata [24]

Answer: $5^6=15,625$

Step-by-step explanation:

To solve this exercise it is important to remembet the definition Definition of a Logarithm:

If $x >0$ and, $b>0,$ $b\neq 1$ , then $y = log_bx$ is equivalent to $b^y=x$ (which is the exponential form).

Knowing this definition and having the following logarithmic equation:

$6=log_515,625$

You can identify that:

$b=5\\y=6\\x=15,625$

Therefore, susbtituting values into $b^y=x$ , you can rewrite this equation as an exponential equation. Then:

$5^6=15,625$

7 0

4 years ago

What is the solution set for 4x+9 <17?<br> Is B right? Or A?

kari74 [83]

Answer:

$x$

Step-by-step explanation:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}$

$4x+9-9$

$\mathrm{Simplify}$

$4x$

$\mathrm{Divide\:both\:sides\:by\:}4$

$=x$

5 0

3 years ago

Read 2 more answers

For a car moving at a constant speed, the distance traveled varies directly with the time spent driving. If such a car travels 5

WINSTONCH [101]

7. What I did is divide 520 by 8 to get the miles and hour. I got 65. Since you can get 65 miles and hour, i divided 455 by 65 to get 7.

3 0

4 years ago

The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic

Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 10

r = number of success

p = probability of success which in our question is % of first-round

appeals that were successful, i.e.; 40%

So, here X ~ $Binom(n=10,p=0.40)$

(a) Probability that none of the appeals will be successful = P(X = 0)

P(X = 0) = $\binom{10}{0}0.40^{0}(1-0.40)^{10-0}$

= $1*0.6^{10}$ = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

P(X = 1) = $\binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= $10*0.4^{1} *0.6^{10-1}$ = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

P(X >= 2) = 1 - P(X = 0) - P(X = 1)

= 1 - $\binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful = P(X > 0.5)

For this probability we will convert our distribution into normal such that;

X ~ N( $\mu = n*p=4,\sigma^{2}= n*p*q = 2.4$ )

and standard normal z has distribution as;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

P(X > 0.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{0.5-4}{\sqrt{2.4} }$ ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0

3 years ago