Answer:
x = 10°
Step-by-step explanation:
a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"
Therefore, in cyclic quadrilateral ABDE,
m∠ABD + m∠AED = 180°
110° + m∠AED = 180°
m∠AED = 180° - 110°
= 70°
b). AD = ED [Given]
m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]
m∠EAD = m∠AED = 70°
By triangle sum theorem in ΔABD,
m∠BAD + m∠ABD + m∠ADB = 180°
m∠BAD + 110° + 40° = 180°
m∠BAD = 180 - 150
= 30°
m∠AEB = m∠AED + m∠DAB [By angles addition postulate]
m∠AEB = 70° + 30°
= 100°
By triangle sum theorem in the large triangle,
x° + m∠AEB + m∠EAB = 180°
x° + 100° + 70° = 180°
x = 180 - 170
x = 10°
Answer:
to the nearest what
Step-by-step explanation:
5x+15-6+7x
15-6= 9.
5=7= 12
12x+9 .
Answer:
![p=10\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D10%5Csqrt%5B3%5D%7B54%7Dx%5E2)
Step-by-step explanation:
We are given parallelogram
Since, two opposite sides of any parallelogram are always equal
Let's assume first side =a
second side =b
so, we get
![a=2\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=a%3D2%5Csqrt%5B3%5D%7B54%7Dx%5E2)
![b=3\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=b%3D3%5Csqrt%5B3%5D%7B54%7Dx%5E2)
now, we can find perimeter
perimeter=2a+2b
so, we get
![p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)](https://tex.z-dn.net/?f=p%3D2%282%5Csqrt%5B3%5D%7B54%7Dx%5E2%29%2B2%283%5Csqrt%5B3%5D%7B54%7Dx%5E2%29)
we can simplify it
![p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D4%5Csqrt%5B3%5D%7B54%7Dx%5E2%2B6%5Csqrt%5B3%5D%7B54%7Dx%5E2)
................Answer