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Sloan [31]
3 years ago
14

Omg wth is this please help :(

Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0
A The surface area of the smallercan is 80%of the surface area of the larger can
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I Need Help Like Now!!
kogti [31]

Answer:

\frac{136}{999}

Step-by-step explanation:

We require 2 equations with the repeating decimal after the decimal point in both equations.

The bar above 136 indicates that 136 is being repeated

let x = 0.136136...... → (1) Multiply both sides by 1000

1000x = 136.136.... → (2)

Subtract (1) from (2) to eliminate the decimal part

999x = 136 ( divide both sides by 999 )

x = \frac{136}{999}

5 0
3 years ago
Please please open !
Tomtit [17]

Answer:

1.A  2.A  3.A 4.B  5.A  6.B

6 0
3 years ago
How many six digit even numbers can be formed that don't end in 0?
Fudgin [204]
1st digit: 9 possibilities (can’t have 0)
2nd digit: 10 possibilities
3rd digit:10
4th digit:10
5th digit:10
6th digit: 4 possibilities (it can only be even)
9•10•10•10•10•4 =360,000 possibilities
8 0
3 years ago
A town has three roads that form an obtuse triangle. James wants to set up a refreshment stand so that the shortest distance fro
GarryVolchara [31]
He should set up the refreshment stand on the incenter of the obtuse triangle. The incenter of a triangle is described as the intersection between the angle bisectors of a triangle. The inradius are the line segments from the incenter of the triangle to each of the three sides of the triangle which are all equal. The inradius is depicted as the radius of an inscribed circle in the triangle. Therefore, the shortest equal distance from his stand to each road is C. on the incenter.
4 0
3 years ago
Find the measures of the four numbered angles
Genrish500 [490]
First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so 
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65
5 0
3 years ago
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