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Murljashka [212]
1 year ago
7

Given: AB = 12

Mathematics
1 answer:
Alexxx [7]1 year ago
3 0

In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

<h3>What is the proof about?</h3>

Note that:

AB = 12

AC = 6.

BC = AB - AC

= 12 - 6

=6

So, AC, BC= 6

Since C is in the middle, one can say that C is the midpoint of AB.

Note that the use of segment addition property shows: AC + CB = AB = 12

Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6

Therefore,  AC = CB and thus In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

See full question below

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive

Learn more about midpoint from

brainly.com/question/6364992

#SPJ1

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