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1 year ago

Given: AB = 12

Mathematics

1 answer:

Alexxx [7]1 year ago

3 0

In proving that C is the midpoint of AB, we see truly that C has Symmetric property.

<h3>What is the proof about?</h3>

Note that:

AB = 12

AC = 6.

BC = AB - AC

= 12 - 6

So, AC, BC= 6

Since C is in the middle, one can say that C is the midpoint of AB.

Note that the use of segment addition property shows: AC + CB = AB = 12

Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6

Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.

See full question below

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive

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The measure of one angle is 13 less than five times The measure of another angle. The sum of the measure of the two angles is 14

kodGreya [7K]

$\huge\boxed{a=\frac{229}{2};\ \ b=\frac{51}{2}}$

<em>In decimal form, a = 114.5; b = 25.5</em>

We will write this as a system of equations, where $a$ and $b$ are the two angles.

$\left \{ {{a=5b-13} \atop {a+b=140}} \right$

We will use substitution to solve this system. We know what $a$ equals, so we plug that into the second equation.

$5b-13+b=140$

Combine the like terms.

$6b-13=140$

Add $13$ on both sides.

$6b=153$

Divide both sides by $6$ .

$b=\frac{153}{6}=\boxed{\frac{51}{2}}$

Now just subtract that from $140$ .

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7 0

2 years ago

PLEASE HELP

Finger [1]

The range of the function is $\{-19,-4,16\}$

Explanation:

The function is $f(n)=5n-4$

The domain of the function is $\{-3,0,4\}$

We need to find the range of the function.

The range can be determined by substituting the values of domain in the function.

Thus, the range of the function when the domain is -3 is given by

$f(-3)=5(-3)-4$

$=-15-4$

$=-19$

Thus, the range is -19 when $n=-3$

The range of the function when the domain is 0 is given by

$f(0)=5(0)-4$

$=0-4$

$=-4$

Thus, the range is -4 when $n=0$

The range of the function when the domain is 4 is given by

$f(4)=5(4)-4$

$=20-4$

$=16$

Thus, the range is 16 when $n=4$

Thus, the range of the function is $\{-19,-4,16\}$ when their corresponding domain is $\{-3,0,4\}$

Arranging the range in order from least to greatest is given by

$\{-19,-4,16\}$

Hence, the range of the function is $\{-19,-4,16\}$

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2 years ago

Mr.rodriguez invests half money in land a tenth in stocks and a twentieth in bonds he puts the remaining 35,000 in his savings a

Elena-2011 [213]

Answer: $100,000

<u>Step-by-step explanation:</u>

Land + Stocks + Bonds + Savings = 100%

$\dfrac{1}{2}x$ + 0.1x + $\dfrac{1}{20}x$ + 35,000 = 1.00x

= 0.5x + 0.1x + 0.05x + 35,000 = 1.00x

= 0.65x + 35,000 = 1.00x

35,000 = 0.35x

$\dfrac{35,000}{0.35}=\dfrac{0.35x}{0.35}$

100,000 = x

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zheka24 [161]

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<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

$\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$

$=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}$

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