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OverLord2011 [107]
3 years ago
5

Which is the exponential form of logb 35=3?

Mathematics
2 answers:
astraxan [27]3 years ago
7 0
B^3=35 ... I think this is the answer
castortr0y [4]3 years ago
7 0

Answer:

Exponential form is

B^3 = 35

Step-by-step explanation:

To convert any log to it's exponential form......let's assume it's

LogcA= B

To it's exponential form is

C raised to power of B is equal to A

C^B = A.

Where C is the base.

So for logb 35=3

Exponential form is

B^3 = 35

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Compare the modeld for one third and two sixths
DochEvi [55]
1/3 is equal to 2/6
This is because 1/3 converted to 6ths you have to multiply 1/3 times 2 which equals 2/6
1/3 = 2/6
4 0
3 years ago
What Value of m will make this equation true? 3 (m - 5) + 8 = 7 - 1/2 (4m - 11)​
KatRina [158]

Answer:

m = 7.1

Step-by-step explanation:

3 (m -5) + 8 = 7 -1/2 (4m - 11)

So, what I did first was distribute the values in the parenthesis to get,

3m - 15 + 8 = 7 -2m -5.5

Now that we have the parenthesis taken care of we can do the simpler math,

3m - 23 = 7 -2m - 5.5

I just added the 15 and 8, so now I move the -5.5 to the opposite side by adding.

3m - 23 = 7 -2m -5.5

<u>        +5.5             +5.5</u>

3m - 28.5 = 7 - 2m

Here we can do the same with the -2m.

3m - 28.5 = 7 - 2m

<u>+2m                 +2m</u>

5m - 28.5 = 7

To get rid of the -28.5 I added it to the 7 getting an answer of,

5m - 28.5 = 7

<u>      + 28.5    +28.5</u>

5m = 35.5

Finally, divide 5m and 35.5 both by 5.

5m/5 = m

35.5/5 = 7.1

Answer: m=7.1

Sorry it's really long, but I hope this helps! Have a great day!

6 0
3 years ago
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

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If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
4 years ago
Write an equation of the circle with center (-7, 4) and radius 8.
Stels [109]

answer

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set up equation

the equation of a circle is (x - h)^2 + (y - k)^2 = r^2

where h is the center x coordinate and k is the center y coordinate

values

from the point (-7,4) we know that h = -7 and k = 4

since the radius is 8, r^2 = 8^2 = 64

plug in values

now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2

(x - h)^2 + (y - k)^2 = r^2

(x - (-7))^2 + (y-4)^2 = 64

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romanna [79]

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Step-by-step explanation:

6 0
3 years ago
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