Q2 goes from 90-180 degrees from the positive x-axis.
So if the line bisects Q2, theta=(90+180)/2=135 degrees.
Sin(135)=+sin(180-135)=+sin(45)=sqrt(2)/2=0.70710678 approx.
Answer:
Money for coach tickets is $1280 and money for first class is $7600
Step-by-step explanation:
8 x 160 = 1280
8x 950 = 7600
1.) The slope equals -5/4 because if we change the 4x+5y=-2 to a slope-intercept form then we can easily see the m (slope) and from that you switch the sign of the number and switch the numbers (ex. -1/2 = 2, 3 = -1/3). To get to the slope-intercept, you subtract 4x from both sides to get 5y=4x-2, then divide both sides by the 5 next to y to get y=4/5x-2/5.
2.) The equation would be y=1/3x+5 because if make the equation into a slope-intercept form by adding the x to both sides to get 3y=x+6 then divide both sides by 3 for y=1/3+2, then we can see the slope is 1/3 and since parallel lines have the same slope, you know the new line's slope is 1/3. Now if we put the slope into a new equation you'll get y=1/3x+b, so you then substitute the point's x and y in the equation for 5=1/3(3)+b, and then solve for b which is 5. Putting the y-intercept (b) and the slope into an equation, you get y=1/3x+5.
Answer:
Step-by-step explanation:
<em>Rule need to remember to solve such questions</em><em>:</em>
Answer:
242
Step-by-step explanation:
Simplify the following:
11 ((9^2 - 5^2)/2^2 + 8)
Hint: | Evaluate 2^2.
2^2 = 4:
11 ((9^2 - 5^2)/4 + 8)
Hint: | Evaluate 5^2.
5^2 = 25:
11 ((9^2 - 25)/4 + 8)
Hint: | Evaluate 9^2.
9^2 = 81:
11 ((81 - 25)/4 + 8)
Hint: | Subtract 25 from 81.
| 7 | 11
| 8 | 1
- | 2 | 5
| 5 | 6:
11 (56/4 + 8)
Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.
The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:
11 (14 + 8)
Hint: | Evaluate 14 + 8 using long addition.
| 1 |
| 1 | 4
+ | | 8
| 2 | 2:
11×22
Hint: | Multiply 11 and 22 together.
| 2 | 2
× | 1 | 1
| 2 | 2
2 | 2 | 0
2 | 4 | 2:
Answer: 242
