Answer:
Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Step-by-step explanation:
We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.
<em>Let X = incomes for the industry</em>
So, X ~ N(
)
Now, the z score probability distribution is given by;
Z =
~ N(0,1)
where,
= mean income of firms in the industry = 95 million dollars
= standard deviation = 5 million dollars
So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)
P(X < 100) = P(
<
) = P(Z < 1) = 0.8413 {using z table]
Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
The equation of a line that passes thruogh the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so
passing through (a,b) and having slope of b is
y-b=b(x-a)
Y-4X =3 ; 2x-3y=21
Y= 3+ 4x
2x -3( 3+4x)= 21
2x- 9- 12x= 21
-10x -9= 21
-10x -9+9= 21+9
-10x = 30
X= 30/-10= -3
Y= 3+4x = 3+ 4* (-3)= 3-12= -9
Answer:
Midpoint (4|7)
Step-by-step explanation:
A(2,6) and B(6,8)
at first add the x values and divide it by two
(2+6)/2=4
second, add the y values and divide it by two
(6+8)/2=7
Midpoint (4|7)
-> and you can see it it is exactly in the middle of line segment