I don't know for sure, but I think the answer is 200
Rewriting the question, the given lengths that were cut from the board were 30 3/4 inches, 12 1/4 inches, and 16 1/4 inches. To obtain the remaining length of the board, all of the measurements cut are to be added and subtracted from 72 inches. This is shown below:
30 3/4 + 12 1/4 + 16 1/4 = 237/4 = 59.25 inches.
Remaining length of board = 72 - 59.25 = 12.75 inches.
Therefore, there will be 12.75 inches remaining of the board.
Answer:
The first step is to determine the largest number that evenly divides the numerator and the denominator (also called the Greatest Common Factor of these numbers). In other words, what's the biggest number that goes into '2' (the numerator) and '4', the denominator?
Step 2. Once you've answered step 1 and realized that, for our fraction at least, the greatest number that evenly divides 2 and 4 is '2'. Now divide the top and the bottom by 2 to get your simplified fraction which is ½.
I hope this helps if you have any questions on my answer plz let me know Ty :3
The rectangle R’S’T’U’ is a 90° counterclockwise rotation of RSTU so options (A) and (C) will be correct.
<h3>What is a rectangle?</h3>
The rectangle is a geometrical figure in which opposite sides are equal.
The angle between any two consecutive sides will be 90 degrees.
Area of rectangle = length × width.
Perimeter of rectangle = 2( length + width).
Given the rectangle RSTU if we plot it then it becomes a major horizontal rectangle.
If we transpose into R’S’T’U’ then it rotates 90 degrees counterclockwise and becomes a major vertical ractangle.
Hence the rectangle RSTU will rotate 90° counterclockwise to form R’S’T’U’.
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The dimensions are 16 ft by 32 ft
The quadratic equation is w^2-256=0
We have given that,
Todd and his brother Robert are going to use 512 square feet of their backyard for skateboard ramps. the shape of the backyard is rectangular, with the length twice as long as the width.
<h3>What is the area of the rectangle?</h3>
The area of a rectangle is equal to
A=WL
Where L is the long side of the rectangle
W is the width side of the rectangle
in this problem we have
A=512ft^2
S0,512=LW -----> equation A
L=2W ------> equation B
substitute equation B in equation A
512=2W(W)
512=2w^2
2w^2-512=0
W^2=512/2
W=\sqrt(256)
W=16
Find the value of L
L=2W
L=2(16)
L=32ft
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