The value of p(1) is 2
<h3>What is the value of p(1)?</h3>
The function definition is given as:
P(x) = -3(x - 2)^2 + 5
The expression P(1) means that x =1
So, we have:
P(1) = -3(1 - 2)^2 + 5
Evaluate the difference
P(1) = -3(-1)^2 + 5
Evaluate the square
P(1) = -3 * 1 + 5
This gives
P(1) = 2
Hence, the value of p(1) is 2
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-3x-2y=30
-2y=3x+30
y=-3/2x-15
the answer is y=-3/2x-15
The distance between the two points is <u>11.3 units.</u>
<em><u>Given</u></em>:
<em>Apply the </em><em>distance formula</em><em> given as:</em>
Let,
<em>Plug in the values</em>
Therefore, the distance between the two points in a coordinate plane is <u>11.3 units.</u>
Learn more about distance on a coordinate plane here:
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