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Neporo4naja [7]
3 years ago
9

BRAINLIEST!!!!!When evaluating , what will be the exponent of 10 in the product?

Mathematics
2 answers:
garik1379 [7]3 years ago
7 0
You're answer here would be 8
PIT_PIT [208]3 years ago
7 0

For this case we have the following multiplication:

(3.25 * 10 ^ 5) (1.82 * 10 ^ 3)

Rewriting the product we have:

(3.25 * 1.82) (10 ^ 5 * 10 ^ 3)

By definition we have to:

In multiplication, if we have the same base we add the exponents.

We have then:

(5.915) (10 ^ {(5 + 3)})\\(5.915) (10 ^ 8)

Answer:

The exponent of 10 in the product will be:

8

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Hey guys ! Can anyone help me with these problems please and thanks
AnnyKZ [126]

1)

m = 3√2√2

= 6

n = a

= 3√2

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2)

m = n = a

m = 3

n = 3

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>=</u><u> </u><u>A</u>

3 0
2 years ago
Points W, K, and
Ksju [112]

Answer:

Points W, K, and J are collinear. Line CA and line YK intersect at point B. Point W is not contained on line m. The answers will be J,B,W

Step-by-step explanation:

Hope this helped :)

5 0
3 years ago
Help help help help math math
aksik [14]

Answer:

8 i think im not really sure

Step-by-step explanation:

3 0
2 years ago
Please help me with geometry
spayn [35]
For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points

------------------------------------------------------

For the points (-10,2) and (-2,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-10))^2+(2-2)^2)

d = sqrt((-2+10)^2+(2-2)^2)

d = sqrt((8)^2+(0)^2)

d = sqrt(64+0)

d = sqrt(64)

d = 8

------------------------------------------------------

For the points (-3,-1) and (5,1), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-(-3))^2+(1-(-1))^2)

d = sqrt((5+3)^2+(1+1)^2)

d = sqrt((8)^2+(2)^2)

d = sqrt(64+4)

d = sqrt(68)

------------------------------------------------------

For the points (-3,-2) and (1,3), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-(-3))^2+(3-(-2))^2)

d = sqrt((1+3)^2+(3+2)^2)

d = sqrt((4)^2+(5)^2)

d = sqrt(16+25)

d = sqrt(41)

------------------------------------------------------

For the points (-3,-5) and (-2,-4), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-3))^2+(-4-(-5))^2)

d = sqrt((-2+3)^2+(-4+5)^2)

d = sqrt((1)^2+(1)^2)

d = sqrt(1+1)

d = sqrt(2)

------------------------------------------------------

For the points (0,0) and (5,5), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-0)^2+(5-0)^2)

d = sqrt((5)^2+(5)^2)

d = sqrt(25+25)

d = sqrt(50)

------------------------------------------------------

For the points (1,2) and (1,-10), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-1)^2+(-10-2)^2)

d = sqrt((0)^2+(-12)^2)

d = sqrt(0+144)

d = sqrt(144)

d = 12

------------------------------------------------------

For the points (1,2) and (5,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-1)^2+(2-2)^2)

d = sqrt((4)^2+(0)^2)

d = sqrt(16+0)

d = sqrt(16)

d = 4

------------------------------------------------------

For the points (2,3) and (10,9), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((10-2)^2+(9-3)^2)

d = sqrt((8)^2+(6)^2)

d = sqrt(64+36)

d = sqrt(100)

d = 10

------------------------------------------------------

See the attached image for how the answers match up (take note of the letter labels)

3 0
3 years ago
Is 5.692 terming or rrepeating
german

Terminating, because it ends. If it was repeating it would go in infinitely, like Pi.

5 0
2 years ago
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