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Vinil7 [7]
3 years ago
12

A sphere with a radius of 5 cm fits inside a box. Every face of the box is tangent to the sphere. What is the ratio of the volum

e of the box to the volume of the sphere?
A.) 6 : pi
B.) 3 : 4pi
C.) 2 : 3pi
D.) 1 : 12pi
Mathematics
2 answers:
BARSIC [14]3 years ago
8 0
Volume of box with side length of 5 = 5^3 = 125

Volume of sphere = (4/3)*pi*5^3 = (4/3)pi * 125

Ratio = 125/(4pi/3)*125  = 1/(4pi/3) = 3/(4pi)

Answer: B
snow_lady [41]3 years ago
8 0

The answer is 6 : pi. Took the test and got it right.

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You are challenged to a lucky draw game. If you draw a face card (K, Q, J) from a standard deck of cards, you earn 10 points. If
sveticcg [70]
There are 3 face cards for each of the 4 suits, leading to a total possible gain of 120, there are 40 other cards leading to a total possible loss of 80.
120 - 80 = 40.
40 / 52 (total number of cards) = about .77

Final Answer:
The expected value of a draw is positive 0.77 points.
Hope I helped :)
7 0
3 years ago
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How many terms are in the expression? 2x + 4y - 3 A) -3 B) 2 C) 3 D) 4
iragen [17]

Answer:

there are 3 terms no.C)

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3 years ago
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4. If your company purchases an annuity that will pay $50,000/year for 10 years at a 11% discount rate, what is the value of the
julsineya [31]

Answer:

The value of the annuity is $326,852.3766.

Step-by-step explanation:

Here is the required formula to find the present value of annuity:

We can find the present value of annuity:

PV = P + P (\frac{1-(1+r)^{-(n-1)} }{r})

Here:

            P = $50,000

            n = represents the number of number of periods

            r = 0.11

PV = 50,000 + 50,5000 (\frac{1-(1+0.11)^{-(10-1)} }{0.11})

PV = $326,852.3766

The value of the annuity is $326,852.3766 i.e. PV = $326,852.3766.

Keywords: discount rate,  present value of annuity

Learn more about present value of annuity from brainly.com/question/13218793

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4 0
3 years ago
I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
The upper quartile of a set of data is the mode of the upper half of the data.true or false
Bad White [126]
False, the upper quartile of a set of data is the median, not the mode
8 0
3 years ago
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