Answer:
8 carnations and 12 zinnias
Step-by-step explanation:
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Answer:
The answer to your question is y = 2x + 11
Step-by-step explanation:
Data
Original line y = -(1/2)x + 5
Point (-4, 3)
Process
1.- Get the slope of the new line
- Slope of the original line = -1/2
If the lines are perpendicular, the slopes must be reciprocal
-1/2 reciprocal = 2
2.- Get the equation of the new line
y - y1 = m(x - x1)
y - 3 = 2(x + 4)
- Simplification
y - 3 = 2x + 8
- Solve for y
y = 2x + 8 + 3
y = 2x + 11
Answer: The length of the rectangle is 35 in.
The width of the rectangle is 28 in.
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Explanation:
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The formula for the area, "A", of a rectangle:
Area (A) = length (L) * width (w) ;
that is: " A = L * w " ;
A = 980 in² (given);
ratio of the length to the width is: " 5 : 4 " (given);
→ Find the length (L) and the width (w).
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→ 980 in² = (5x) * (4x) ;
in which: " 980 in² " is the area of the triangle;
" 5x" = the length (L) of the rectangle, for which we shall solve;
" 4x" = the width (w) of the rectangle, for which we shall solve.
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If we find solve for "x" ; we can solve for "5x" and "4x" (the "length" and the "width", respectively); by plugging in the solved value for "x" ;
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→ 980 in² = (5x) * (4x) ;
↔ (5x) * (4x) = 980 in² ;
→ (5x) * (4x) = (5) * (4) * (x) * (x) = 20 * x² = 20x² ;
→ 20x² = 980 ;
Divide each side by "10" ; by canceling out a "0" on each side of the equation:
→ 2x² = 98 ;
Now, divide each side of the equation by "2" ;
→ 2x² / 2 = 98 / 2 ;
to get:
→ x² = 49 ;
Now, take the "positive square root" of each side of the equation; (since a "length or width" cannot be a "negative value") ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ ⁺√(x²) = √49 ;
to get:
→ x = 7 ;
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Now, we can solve for the "length" and the "width" ;
→ The length is: "5x" ;
5x = 5(7) = " 35 in " ;
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→ The width is: "4x" ;
4x = 4(7) = "28 in."
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Let us check our answer:
→ A = L * w ;
→ 980 in² = ? 35 in. * 28 in. ?? ;
Using a calculator: "35 * 28 = 980" . Yes! ;
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{ Also note: " in * in = in² " ? Yes! } .
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We have to determine the equation of the line passing through the point (2,-5) and parallel to the line 
When two lines are parallel, then the slopes of the two lines are equal.
Equation of line with point
and slope 'm' is given by:

Since, we have to determine the equation of a line with point (2,-5).
So, the equation of the line is : 

Since, the line is parallel to the line 
So, 


So, slope of the line 'm' is
.
Therefore, the equation of the line is:




Therefore,
is the required equation of the line.