Answer:
S= z (y-x)/(x+y)
Step-by-step explanation:
Lets the speed of high speed train = u
Lets the regular speed train = v
We know that
Distance = Speed x time
For high speed train
z = u .x
u= z/x ----------1
For regular speed train
z = v .y
v = z/y -------------2
Both are traveling in opposite direction so relative speed
Vr = z / x+ z /y
Lets in time t they will meet
z = (z / x+ z /y) t
t= xy/ (x+y)
Lets take distance cover by high speed train is m when it moves A to B and speed cover by regular train is n when it is moving B to A.They meet at time t.
m = u .t
m = z / x .xy/ (x+y)
m = zy/ (x+y) -----------3
n = v .t
n = z / y .xy/ (x+y)
n = zx/ (x+y) -----------4
From equation 3 and 4
So
m - n= zy/ (x+y) - zx/ (x+y)
S= z (y-x)/(x+y)
Option a is correct.
Answer:
Step-by-step explanation:
<u>Ball dropped and we start count from that moment:</u>
- 160 ft down
- 80 ft up and down
- 40 ft up and down
- 20 ft up and down, end
<u>Total distance:</u>
- 160 + 80*2 + 40*2 + 20*2 = 440 ft
Answer:
(x+1, y-3)
Step-by-step explanation:
Because moving x by positive one means that you shift the shape to the right, and subtracting the y by 3 means moving it down by three. I solved it by choosing one point and figuring out how the same point ended up where it is after the translation (I looked at point a and saw how much it moved right and down). Hope this helps! :)
divide 50 by 6.2, because 6.2 and x are entangled by multiplication. once you do that, you will have your answer. it should be 8.06
For #1. Step 1: Set the equations equal to one another: (3x + 20) = (2x + 40)
Step 2: Subtract 2x on both sides of the equal sign: (3x-2x + 20) = (2x-2x + 40)
x + 20=40
Step 3: Subtract 20 on both sides of the equal sign: x + 20-20= 40-20
x=20
Step 4: plug in 20 for x: 3(20) + 20= 80 & 2(20) + 40= 80
