Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
Hey there!!
How do we find the equation of a line ?
Ans : We take the slope and the y - intercept and get them together.
How do you find slopes?
Ans - In order to find slop, we will need to use the slop formula which is
( y₂ - y₁ ) / ( x₂ - x₁ )
The two points shown in the above question are
( 4 , -8 ) and ( 8 , 5 )
y₂ = 5 , y₁ = -8 and x₂ = 8 , x₁ = 4
Now plug in the values:
( 5 + 8 ) / ( 8 - 5 )
13 / 3
Hence, the slope is 13/3
The basic formula : y = mx + b
Where b is the y-intercept and m is the slope.
We have found the slope, hence, the formula would become
... y = 13/3 x + b
Now take a coordinate and substitute it .
I will take ( 8 , 5 )
x = 8 and y = 5
Now plug in the values
... 5 = 13/3 × 5 + b
... 5 = 65/3 + b
Subtract 65/3 on both sides
... 5 - 65/3 = b
... -50/3 = b
Hence, the y-intercept is -50/3
Now plug in all the values to get the total equation...
The final equation : y = 13x/3 - 50/3
... y = 13x - 50 / 3
Hope my answer helps!!
Answer:
Step-by-step explanation:
So, we know that the center of the circle is at (-6, -7/6).
To find the equation of our circle that is tangent to the x-axis, we just need to find the vertical distance from our center to the x-axis.
Our center is at (-6, -7/6). The vertical distance from this to the x-axis directly above will be (-6, 0).
So, find our distance by subtracting our x-values:
Subtract:
So, our distance, which is also our radius, will be 7/6.
Now, we can use the standard form for a circle, which is:
Where (h, k) is the center and r is the radius.
Substitute -6 for h, -7/6 for k, and 7/6 for r. This yields:
We can confirm by graphing (using a calculator):
Answer:
I am pretty sure it's −2.7710843373
