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3 years ago

8.3+3.4y-0.5(12y-7) Simplified

Mathematics

2 answers:

sesenic [268]3 years ago

5 0

-2.6y+11.8 is the solution.

Hope I'm the brainliest

kogti [31]3 years ago

5 0

The answer is -2.6y+11.8

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Answer:

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2 years ago

Read 2 more answers

The NCAA is interested in estimating the difference in mean number of daily training hours for men and women athletes on college

hammer [34]

Answer:

$s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125$

$s_p =\sqrt{0.125}=0.354$

$(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032$

$(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

$\bar X_M = 2.7$ represent the sample mean for men