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RUDIKE [14]
3 years ago
12

Which expression is equal to sec x° multiplied by cot x°?

Mathematics
2 answers:
melomori [17]3 years ago
5 0
The answer is D. hypotenuse ÷ opposite
ExtremeBDS [4]3 years ago
5 0

Answer:

D) hypotenuse ÷ opposite.

Step-by-step explanation:

Given  : sec x° multiplied by cot x°.

To find : Which expression.

Solution : We have given  that

sec x°  * cot x°.

We know that  sec x° =  \frac{hypotenuse}{adjacent}.

cot x° =  \frac{adjacent}{opposite}.

Then

sec x°  * cot x° =  \frac{hypotenuse}{adjacent} * \frac{adjacent}{opposite}.

On simplification

sec x°  * cot x° = \frac{hypotenuse}{opposite}.

Therefore, D) hypotenuse ÷ opposite.

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Step-by-step explanation:

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ohaa [14]

Answer:

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Step-by-step explanation:

Fact:

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In other words, (a^{2} - b^{2}), the difference of two squares in the form a^{2} and b^{2}, could be factorized into (a - b)\, (a + b).

In this question, the expression (9\, w^{2} - 100) is the difference between two terms: 9\, w^{2} and 100.

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Hence:

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Apply the fact that a^{2} - b^{2} = (a - b) \, (a + b) to factorize this expression. (In this case, a = 3\, w whereas b = 10.)

\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}.

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