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lana [24]
3 years ago
14

What is the area of this triangle?

Mathematics
1 answer:
omeli [17]3 years ago
8 0

Answer:

13.1 cm^2

Step-by-step explanation:

i dont have an explanation :)

if this is incorrect please comment so i can re do thanks

hope this helps :)

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What is -32÷-(8)-8r+10(r-6)
timurjin [86]

Answer:

The answer should be 2r - 56


Sorry if im wrong

Step-by-step explanation:


7 0
3 years ago
Help pleaseeeeee anyoneee?
steposvetlana [31]

Answer:

z = -9.538546756+ 15.26486573i

Step-by-step explanation:

z = |z| cos theta + |z| i sin theta

 We know |z| and theta

z = 18 cos 122 +18i sin 122

z = -9.538546756+ 15.26486573i

3 0
4 years ago
−5x+2y=9<br> y=7x<br> ​x=<br> y=
Serhud [2]

- 5x+2y=9 \\ y=7x

We know that y=7x, so we just need tu put it into the 1st equation

- 5x + 2 \times 7x = 9 \\  - 5x + 14x = 9 \\ 9x = 9 | \div 9 \\ 9x \div 9 = 9 \div 9 \\ x = 1

So we found x. Now we can find y

y = 7 \times 1 \\ y = 7

Answer:

x=1, y=7; or (1;7)

4 0
3 years ago
The ratio of the areas of two rectangle is 3 to 7. In the area of the large rectangle is 84 square feet, what is the area of the
goldenfox [79]
A. The unknown variable is the area of the smaller rectangle.

B. 3/7=x/84

\frac{3}{7}=\frac{x}{84}\\\frac{3*12}{7*12}=\frac{x}{84}\\\frac{36}{84}=\frac{x}{84}\\\frac{36}{84}*84=\frac{x}{84}*84\\36=x

C. No. 12 does not equal 15.

\frac{3}{7} \neq \frac{15}{28}\\\frac{3*4}{7*4}\neq\frac{15}{28}\\\frac{12}{28}\neq\frac{15}{28}\\\frac{12}{28}*28\neq\frac{15}{28}*28\\12\neq15
5 0
3 years ago
What is the total area of the regions between the curves y = 6x2 − 18x and y = −6x from x = 1 to x=3?.
kvasek [131]

Using integration, it is found that the area between the two curves is of 22 square units.

<h3>What is the area between two curves?</h3>

The area between two curves y = f(x) and y = g(x), in the interval from x = a to x = b, is given by:

A = \int_{x = a}^{x = b} |f(x) - g(x)| dx

In this problem, we have that:

f(x) = 6x^2 - 18x, g(x) = -6x, a = 1, b = 3.

Hence, the area is:

A = \int_{1}^3 |6x^2 - 12x| dx

A = |x^3 - 6x^2|_{x = 1}^{x = 3}

Applying the Fundamental Theorem of Calculus:

A = |3^3 - 54 - 1^3 + 6|

A = 22

The area between the two curves is of 22 square units.

More can be learned about the use of integration to find the area between the two curves at brainly.com/question/20733870

8 0
3 years ago
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