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Eduardwww [97]
2 years ago
14

Total money of 2 quarters, 1 dime, 3 pennies

Mathematics
2 answers:
Makovka662 [10]2 years ago
8 0
You would have sixty three cents
Tju [1.3M]2 years ago
7 0
You have 2 quarters, 1 penny, 3 dimes, so
1 quarter = 25 cents
3 penny  =  1 cent
1 dimes  = 10 cents
So 25 cents + 25 cents = 50 cents
50 cents + 3 cents = 53 cents
53 cents + 10 cents = 63 cents
I hope this helps you today with this problem : )
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State the number of real zeros and what they are for "3x^2+5x-2" pleas help me:'(
Lady bird [3.3K]
This can be solved by factoring.

First, set the expression equal to zero.

3x^2+5x-2=0

Then, find two the factors of  ac whose sum is b.

6, -1

Split b into these two factors.

3x^2+6x-x-2=0

Next, factor by grouping.

3x(x+2)-1(x+2) = (3x-1)(x+2) = 0

By the Zero Product Property, set each factor equal to zero.

3x-1 = 0 \\ x = 1/3

x+2=0 \\ x = -2

These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree n has exactly n complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done. Your answers are -2 and 1/3. There are two real roots.
3 0
3 years ago
A cable car starts off with n riders. The times between successive stops of the car are independent exponential random variables
nikitadnepr [17]

Answer:

The distribution is \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}

Solution:

As per the question:

Total no. of riders = n

Now, suppose the T_{i} is the time between the departure of the rider i - 1 and i from the cable car.

where

T_{i} = independent exponential random variable whose rate is \lambda

The general form is given by:

T_{i} = \lambda e^{- lambda}

(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:

S_{n} = T_{1} + T_{2} + ........ + T_{n}

S_{n} = \sum_{i}^{n} T_{n}

Now, the sum of the exponential random variable with \lambda with rate \lambda is given by:

S_{n} = f(t:n, \lamda) = \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}

5 0
3 years ago
How many centimeters are there in 1.23 x 10 to the negative 6th power
pashok25 [27]
I think the answer is <span>0.123 cm</span>
4 0
3 years ago
Help please . will give brainliest ​
marishachu [46]

Answer:

A

Step-by-step explanation:

the last number is the y intercept so the intercept in the line is -3.5 so I just matched them up.

3 0
3 years ago
How to reduce into simpler terms.?
Sveta_85 [38]

Answer:

The simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

  • A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.
  • In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

\frac{45}{100}

\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}

\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5

\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}

45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20

so

\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}

\mathrm{Cancel\:the\:common\:factor:}\:5

     =\frac{9}{20}

Therefore, the simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

4 0
3 years ago
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