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Tresset [83]
3 years ago
6

Jason earned scores of 90 points, 82 points, 95 points, and 86 points on four tests. What is the lowest score he can get on the

fifth test and still finish with an average score of 90 points?
95 points
96 points
97 points
98 points
Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
Hi, the answer is 97 points. I hope this helps.
azamat3 years ago
8 0

Answer:

97 points

Step-by-step explanation:

Given,

His scores, in first test = 90 points,

In second test = 82 points,

In third test = 95 points,

In fourth test = 86 points,

Let he scores x points on the fifth test,

Thus, the total sum of the scores in five tests = 90 + 82 + 95 + 86 + x

= 353 + x

Also, The Average scores in these five test = 90

We know that,

\text{Average score}=\frac{\text{Total sum of the scores}}{\text{Total number of tests}}

Here, total number of tests = 5,

90=\frac{353+x}{5}

450=353+x\implies x = 450-353=97

Hence, the lowest score he can get on the fifth test and still finish with an average score of 90 points is 97 points.

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(D) P-val=0.021, fail to reject the null hypothesis

Step-by-step explanation:

1) Data given and notation  

\bar X=21.5 represent the mean for the temperatures

s=1.5 represent the sample standard deviation

n=40 sample size  

\mu_o =22 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

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Null hypothesis:\mu \geq 22  

Alternative hypothesis:\mu < 22  

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t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

P-value

We can calculate the degrees of freedom like this:

df=n-1=40-1=39

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p_v =P(t_{39}  

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