Answer:
y = -2x + 8
Step-by-step explanation:
The point slope form of an equation is written as
y = mx + c ...............(i)
Where m is the slope and c is the constant
Now we Know that the equation is
y + 2 = -2(x-5)
and the given points are
m= -2
x = 5
and y= -2
Putting these values in equation (i) to find the value of c
y = mx + c
it becomes
-2 = -2(5) + c
-2 = -10 + c
Adding 10 on both sides
-2 + 10 = -10 + 10 + c
8 = c
or c=8
Now we have the values of m and c
where m= -2 and c = 8
Point slope form of an equation is
y = mx + c
putting the values of m and c to get equation in slope intercept form is
y = (-2)x + 8
or
y = -2x + 8
Other method:
The given point slope form is
y + 2 = -2(x-5)
We have to change it in y= mx + c form
so solving it
y + 2 = -2x + 10
Subtracting 2 from both sides
y + 2 -2 = -2x + 10 -2
y = -2x + 8
which is same is
y=mx + c
so the required equation is
y = -2x + 8
X-1= 5x+3x-8
Combine like terms
x-1= 8x-8
Our goal is to isolate x by cancelling out other numbers.
Subtract x from both sides
x-1-x= 8x-x-8
-1= 7x-8
Add 8 to both sides
7=7x
Divide both sides by 7
1=x
Final answer: x=1
Answer:
a) P=0.3174
b) P=0.4232
c) P=0.2594
d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.
Step-by-step explanation:
The appropiate distribution to model this is the hypergeometric distribution:
![P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%5Cfrac%7B%5Cbinom%7Bs%7D%7Bx%7D%5Cbinom%7BN-s%7D%7BM-x%7D%7D%7B%5Cbinom%7BN%7D%7BM%7D%7D%3D%5Cfrac%7B%5Cbinom%7B6%7D%7Bx%7D%5Cbinom%7B54%7D%7B10-x%7D%7D%7B%5Cbinom%7B60%7D%7B10%7D%7D)
a) What is the probability that none of the questions are essay?
![P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174](https://tex.z-dn.net/?f=P%28X%3D0%29%3D%5Cfrac%7B%5Cbinom%7B6%7D%7B0%7D%5Cbinom%7B54%7D%7B10-0%7D%7D%7B%5Cbinom%7B60%7D%7B10%7D%7D%5C%5C%5C%5CP%28X%3D0%29%3D%5Cfrac%7B1%2A%2854%21%2F%2810%21%2A44%21%29%7D%7B60%21%2F%2810%21%2A50%21%29%7D%20%3D%5Cfrac%7B2.3931%2A10%5E%7B10%7D%7D%7B7.5394%2A10%5E%7B10%7D%7D%20%3D%200.3174)
b) What is the probability that at least one is essay?
![P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232](https://tex.z-dn.net/?f=P%28X%3D1%29%3D%5Cfrac%7B%5Cbinom%7B6%7D%7B1%7D%5Cbinom%7B54%7D%7B9%7D%7D%7B%5Cbinom%7B60%7D%7B10%7D%7D%5C%5C%5C%5CP%28X%3D1%29%3D%5Cfrac%7B6%2A%2854%21%2F%289%21%2A43%21%29%7D%7B60%21%2F%2810%21%2A50%21%29%7D%20%3D%5Cfrac%7B3.1908%2A10%5E%7B10%7D%7D%7B7.5394%2A10%5E%7B10%7D%7D%20%3D0.4232)
c) What is the probability that two or more are essay?
![P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594](https://tex.z-dn.net/?f=P%28X%5Cgeq2%29%3D1-%28P%280%29%2BP%281%29%29%3D1-%280.3174%2B0.4232%29%3D1-0.7406%3D0.2594)
Answer:
x= 7![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Step-by-step explanation:
It's a 45 45 90 triangle
The legs are = x while the hypotenuse is x
.
Therefore the answer is 7![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)