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Amiraneli [1.4K]
4 years ago
6

How can you check if two rays are perpendicular

Mathematics
2 answers:
cluponka [151]4 years ago
6 0
They should have a 90-degree angle in between them.

yanalaym [24]4 years ago
5 0
If they are perpendicular, they intersect each other
So unless the two lines are parallel, then the lines will intersect at some point
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use the change of base formula to evaluate log[3](58). then convert log[3](58) to a logarithm in base 4?
devlian [24]
Log[3](58)=3.69597450
log[3](58) to a logarithm in base 4= 167.957<span>
if you still need it.</span>
3 0
3 years ago
From least to greatest 8/100 3/5 7/10
stich3 [128]
8/100, 3/5, 7/10

Explanation:
8/100 = 0.08
3/5 = 0.6
7/10 = 0.7
6 0
3 years ago
Read 2 more answers
Find the distance between (2,3) and (-4,9). If you get a radical (square
9966 [12]

Answer:

<u>Length</u><u> </u><u>is</u><u> </u><u>6</u><u>√</u><u>2</u><u> </u><u>units</u><u> </u><u>or</u><u> </u><u>8</u><u>.</u><u>4</u><u>9</u><u> </u><u>units</u>

Step-by-step explanation:

Length formular:

length =  \sqrt{ {(x _{2}  - x_{1}) }^{2} +  {(y_{2} - y_{1})}^{2}  }

x1 is 2

x2 is -4

y1 is 3

y2 is 9

length =  \sqrt{ {( - 4 - 2)}^{2}  +  {(9 - 3)}^{2} }  \\  \\  =  \sqrt{ {( - 6)}^{2} +  {6}^{2}  }  \\  \\  =  \sqrt{36 + 36}  \\  =  \sqrt{2 \times 36}  \\  =  \sqrt{2}  \times  \sqrt{36}  \\  { \boxed{ \boxed{= 6 \sqrt{2} }}} \\  = 8.49 \: units

8 0
3 years ago
Divide. 603 ÷ 27 = _____ <br> 22 R11 <br> 27 R1 <br> 22 R9 <br> 21 R16
mylen [45]

Answer:

C) 22 R9

Step-by-step explanation:

3 0
3 years ago
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In ΔNOP, the measure of ∠P=90°, the measure of ∠N=27°, and PN = 50 feet. Find the length of NO to the nearest tenth of a foot.
Evgen [1.6K]

Answer:56.1

Step-by-step explanation:

Clicked see solution

6 0
3 years ago
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