Question

A cylinder vase has a height of 10 inches and a diameter of 3 inches. If the water raises to 9/10 of the way to the top, approximately how much water, in cubic inches, is in the vase? Use the symbol on your calculator and round to the nearest cubic inch.

Answer 1

Answer:

The volume of water in the vase is $64 in^3$

Step-by-step explanation:

A cylinder vase has a height, h, of 10 inches and its diameter of 3 inches. This means that its radius, r, is:

r = 3 / 2 = 1.5 inches

To find the volume of the water in the vase if the water raises to 9/10 of the way to the top, we first have to find the volume of the vase when it is filled with water and then, find 9/10 of that volume.

The volume of a cylinder is given as:

$V = \pi r^2h$

The volume of the vase will be:

$V = \pi * 1.5^2 * 10\\V = 70.69 in^3$

Hence, the volume of the water in the vase when it is 9/10 filled is:

$\frac{9}{10} * 70.69 = 63.62 in^3$

Approximating to the nearest cubic inch, the volume of water in the vase is $64 in^3$