Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The level of significance is 
From the z table the critical value of 
considering the two tails of the normal curve( This is because this a two tailed test ) is
Hence the critical value is
<h3>Hey .... </h3>
here's your answer in the given attachment
Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)
a.) When we reflect over xz plane x and z coordinates stay same, y coordinate changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.
A(0,0,0)
Reflecting
A(0,0,0)
B(0,5,0)
Reflecting
B(0,-5,0)
C(3,5,0)
Reflecting
C(3,-5,0)
D(3,0,0)
Reflecting
D(3,0,0)
b.)
A(0,0,0)
Moving
A(-2,-3,1)
B(0,-5,0)
Moving
B(-2,-8,1)
C(3,-5,0)
Moving
C(1,-8,1)
D(3,0,0)
Moving
D(1,-3,1)
The eigenvector of matrix A4 is 4096.
The eigenvalue of the matrix A-1 is 1/8.
(A+4I) has an eigenvalue of 12.
40 is the eigenvalue of 5Av.
The collection of scalar values known as the eigenvalues of a matrix are connected to the set of linear equations that are most likely contained within the matrix equations.
The eigenvectors are also known as the characteristic roots.
If the matrix A's eigen vector v is linked to an eigen value.
Av then equals lamda v.
The fact that v is an eigen vector of A with the value eight is assumed.
hence, Av = 8v.
We must determine the eigenvalue of A4.
A4*v equals A3(8v) = 84*v equals 4096v.
As a result, the eigenvalue of A4 is 4096.
Suppose A has an eigenvalue of 8. The eigenvalue of A-1 is thus 1/8.
It is calculated that the eigenvalue of (A+4I) is (A +4In)v = Av + 4v = 8v + 4v =12v.
(A+4I) has an eigenvalue of 12.
The value of 5Av's eigenvalue is 5Av = 5*8v = 40v.
40 is the eigenvalue of 5Av.
Learn more about the eigen vectors here:
brainly.com/question/15423383
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