1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrej [43]
3 years ago
9

Need answer ASAP this assignment is due tomorrow

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

Venn diagrams, De'moivres rule and probability

Step-by-step explanation:

You might be interested in
The library is to be given 5 books as a gift. the books will be selected from a list of 21 titles. if each book selected must ha
Natali5045456 [20]

This is a combination problem. Order does not matter and the books are all different. You would write this as 21C5 or \tbinom{21}{5}. Combinations are not fractions.

The answer is \frac{21 * 20 * 19 * 18 * 17}{1 * 2 * 3 * 4 * 5}

which = 20349 different ways these books can be chosen.


5 0
3 years ago
Read 2 more answers
What is the slope of the line passing through the points (12,16) and (8,16)
kap26 [50]

Answer:

I got   Y=0/4x+16 I'm not that sure.

Step-by-step explanation:

6 0
3 years ago
Daily high temperatures in St. Louis for the last week were as​ follows: 95​, 92​, 93​, 92​, 95​, 90​, 90 ​(yesterday). ​a) The
hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as​ follows:

                                   95​, 92​, 93​, 92​, 95​, 90​, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the​ 2-day moving average​

Solution:

a)

- The set of 3 day moving average is as follows:

4.   (95 + 92 + 93) ÷ 3 = 93.33⁰C

5.  (92 + 93 + 92) ÷ 3 = 92.33⁰C

6.  (93 + 92 + 95) ÷ 3 = 93.33⁰C

7.  (92 + 95 + 90) ÷ 3 = 92.33⁰C

8.  (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3.   (95 + 92) ÷ 2 = 93.5⁰C

4.  (95 + 93) ÷ 2 = 92.5⁰C

5.  (93 + 92) ÷ 2 = 92.5⁰C

6.  (92 + 95) ÷ 2 = 93.5⁰C

7.  (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

                             Error             Error^2

3.   93.5⁰C            0.5                  0.25

4.   92.5⁰C            0.5                  0.25

5.   92.5⁰C            2.5                  6.25

6.   93.5⁰C            3.5                  12.25

7.   92.5⁰C            2.5                  6.25

8.   90⁰C

- The mean absolute deviation as follows:

                              MAD = Sum of all errors  / 5

                              MAD = (0.5+0.5+2.5+3.5+2.5)  / 5

                              MAD = 1.9

d)

- The mean squared error deviation as follows:

                              MSE = Sum of all error^2  / 5

                              MSE = (0.25+0.25+6.25+12.25+6.25)  / 5

                              MSE = 5.05

4 0
3 years ago
 FIRST GETS BRAILIEST Michael finds that 35 customers at his grandfather's grocery store use a coupon. To simulate the behavior
Nataly [62]

Answer:

\frac{1}{3}.

Step-by-step explanation:

We are given that,

1, 2, 3 represents someone using a coupon and 4, 5 represents someone not using a coupon.

Now, the results out of 15 trials of the experiment are given to be:

43454, 24511, 55555, 43453, 55315, 25215, 32235, 43311, 11154, 13342, 42514, 13223, 44215, 45313, 13324.

Since, we can see that, the only possibilities where 4 or more customers use coupons are:

32235, 43311, 13342, 13223 and 13324.

That is, out of 15 trials, there are total 5 trials in which 4 or more customers use coupons.

Thus, the probability of 4 or more customers using a coupon is \frac{5}{15} = \frac{1}{3}.

Hence, the required probability is \frac{1}{3}.

8 0
3 years ago
Complete the following ratio table
Nady [450]
Could help if you showed the rest of the table
6 0
3 years ago
Other questions:
  • -3(x+2)=2(x-3)+2 what is the solution?
    14·1 answer
  • Determine the slope of a line that passes through A(-4, 7) and B(6,3)
    10·2 answers
  • The cost of renting a car is $35/wk plus $0.25/mi traveled during that week. An equation to represent the cost would be y = 35 +
    9·1 answer
  • 3x+1+2x=2+4x which would not be a step in solving
    13·1 answer
  • Wich are the solutions of X2 = -5x + 8
    11·1 answer
  • What is the difference between a line, line segment, and a ray?​
    12·2 answers
  • Solve for x.........
    7·2 answers
  • Solve for x, and JUSTIFY your answer.
    14·1 answer
  • 5/2<br> Irrational<br> Rational
    11·1 answer
  • A hen costs $4 and chicks are sold at 3 for $2. A farmer paid $100 exactly for 80 of these birds. How many of each type did he b
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!